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6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD Locate the centroid above the base and the moment of inertia (Ix) of the ii. cross-section ii. What is the highest value of P allowed? 200 P 15.0 15.00 230 2.00 m 2.00 m 15.00 8.00 m 6.00 150 Note: Self-weight may be ignored CECT ON

6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD Locate the centroid above the base and the moment of inertia (Ix) of the ii. cross-section ii. What is the highest value of P allowed? 200 P 15.0 15.00 230 2.00 m 2.00 m 15.00 8.00 m 6.00 150 Note: Self-weight may be ignored CECT ON

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Final Test review 6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD Locate the centroid above the base and the moment of inertia (Ix) of the cross-section What is the highest value of P allowed? II. 200 P 15.0 15.00 230 2.00 m 2.00 m 15.0 8.00 m 6.0d 150 Note: Self-weight may be ignored CROSS - SECTION Answers: (i) Note: Student should draw the SFD, BMD and Deflected shape. Use the coordinates given below to check answers. SFD: (0.00m, P kN): (2.00m, P kN); (6.00m, -P kN), (8.00m, -P kN) BMD: (0.00m, 0.00 kNm): (2.00m, 2P kNm); (6.00m, 2P kNm), (8.00m, 0.00 kNm) Deflected shape: smile throughout! (ii) y = 157 mm from base; Ix = 85.6 x 106 mm4 At N.A., Q = 397.6 × 10³ mm³. Using fy = VQ/(It) where fy = 40.0 N/mm2, t = 6.00 mm Ix = 85.6 x 106 mm“ and V = P yields P = 51.7 kN (iii) Using fb = (M/1)y where fb = 100 N/mm2, y = 157 mm, Ix = 85.6 x 106 mm“ and M = 2P yields P = 27.2 kN. The Point load allowable is the less of the two values computed above. Therefore P = 27.2 kN
Transcribed Image Text:Final Test review 6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD Locate the centroid above the base and the moment of inertia (Ix) of the cross-section What is the highest value of P allowed? II. 200 P 15.0 15.00 230 2.00 m 2.00 m 15.0 8.00 m 6.0d 150 Note: Self-weight may be ignored CROSS - SECTION Answers: (i) Note: Student should draw the SFD, BMD and Deflected shape. Use the coordinates given below to check answers. SFD: (0.00m, P kN): (2.00m, P kN); (6.00m, -P kN), (8.00m, -P kN) BMD: (0.00m, 0.00 kNm): (2.00m, 2P kNm); (6.00m, 2P kNm), (8.00m, 0.00 kNm) Deflected shape: smile throughout! (ii) y = 157 mm from base; Ix = 85.6 x 106 mm4 At N.A., Q = 397.6 × 10³ mm³. Using fy = VQ/(It) where fy = 40.0 N/mm2, t = 6.00 mm Ix = 85.6 x 106 mm“ and V = P yields P = 51.7 kN (iii) Using fb = (M/1)y where fb = 100 N/mm2, y = 157 mm, Ix = 85.6 x 106 mm“ and M = 2P yields P = 27.2 kN. The Point load allowable is the less of the two values computed above. Therefore P = 27.2 kN
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