3.4-2 The tension member shown in Figure 3.4-2 is a PL 5 × 10, and the steel is A36. The bolts are 7/8-inch in diameter. a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. 2" 3" 2" |27|27|--|--| 3" О 2" FIGURE P3.4-2
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- The truss below is pin connected at A and E, and is acted on by the forces shown. E A D B Identify all of the ZERO-FORCE MEMBERS by checking the boxes below (if there are none, leave all boxes unchecked): BF AF BC BH CD EG -GH AB CH DG DH DE -FHDesign the reinforcements of the given T beam below. bf=900mm bw=420mm tf-120mm d=550mm d'=80mm fc'=34MPa fy=415MPa USE NSCP 2015 A.Mu = 1300kN-m, As = mm2 B.Mu = 1800kN-m, As = mm2, As' = mm2Asap pls
- 2- A 2m COPPER BAR SUBJECTEO TO A TENSILE IS SUSPENDED FROM A LOAD IBO KN SUPPORTED BY TWO IDENTICAL PIN THAT S pOSIS AS SHON OF THE LOWER AFPLIED TENSILE POSTS SUPPORT THE STEEL DETERMINE THE TOTAL DEFORMATION END OF THE LOAD HINT: NOTE THAT THE STEEL PIN WHERE THE COFPER BAR IS ATTACHED. COPPER BAR DUE TO STEEL POST L=0.5m A= 4500mm E- 200GPA COPFER BAR L- am A= 4800 Mn E- l20 GPa 180KNDetermine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117civil engineering-AISC Steel Construction
- Select all zero-force members in the truss shown below. Check the box for zero- force members 3 m 3 m 12 m, 8 @ 1.5 m DE O LK ЕР O HF O BC BM EF OM CD BN LO O DK FI O coA PL 38 X 6 tension member is welded to a gusset plate as shown. The steel is A36 (Fy = 36ksi, Fu = 58ksi). a. The design strength, Pu based on gross area b. The design strength, Pu based on effective area PL % x6 3/8" 6" Cross Sectional area of PL3/8x6 a) Blank 1 b) Blank 2A 16 mm thick tension member is connected by two 6.25 mm spliced plates as shown. The tension member carries a service loads of dead load of 110 kN and a live load of 100 kN. 40, 80 , 40 , 40, 80 40 1625 mm 16 mm 1625 mm Fy 248 MPa Fu = 400 MPa Diam. of bolts = 16 mm Fnv = 300 MPa O Determine the nominal strength for one bolt due to shear. O Determine the nominal strength for one bolt due to bearing strength of the connection. ® Determine the number of bolts required for the connection.
- SOLVE FOR THE FORCE IN MEMBERS AB, AC, BC, CD, BD, BE, DE, DF & EF. SHOW SOLUTIONS CLEARLY USING METHOD OF JOINTS AND WRITE WELL ALSO SEE LINK UNDER WEEK7 0.8m 2.4m -6KN MEMBER AB AC BC CD BD BE 2m ED DF EF 1m 8KN Av REACTION hinge) EX REACTION @roller) 3m SUMMARY OF RESULTS FORCE 1m 10KN 2.4m 3KN NATURE(I or C)A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H G P P D B F C A EA PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H FO E. • D A В