A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below: Depth (m) Cone resistance, 9c (MN/m²) 2.0 3.5 5.0 2.67 3.8 4.69 6.5 8.0 8.78 11.75 The average unit weight of the sand is 16.5 kN/m³. Assume moderately compressible sand and hence Qc = Determine the relative density at each depth using the equation below. Яс 1 Dr = 305QOCR 1.8 Ра σ' 0 Pa 0.5 (Enter your answers to three significant figures.) Depth (m) Dr (%) 2.0 3.5 5.0 6.5 8.0 = 1.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below:

Depth   Cone resistance,  
   
   
   
   
   

The average unit weight of the sand is . Assume moderately compressible sand and hence .

Determine the relative density at each depth using the equation below.

 

(Enter your answers to three significant figures.)

Depth    
   
   
   
   
   
 
 
A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below:
Depth (m) Cone resistance, 9c (MN/m²)
2.0
3.5
5.0
2.67
3.8
4.69
6.5
8.0
8.78
11.75
The average unit weight of the sand is 16.5 kN/m³. Assume moderately compressible sand and hence Qc =
Determine the relative density at each depth using the equation below.
Яс
1
Dr
=
305QOCR 1.8
Ра
σ'
0
Pa
0.5
(Enter your answers to three significant figures.)
Depth (m) Dr (%)
2.0
3.5
5.0
6.5
8.0
= 1.
Transcribed Image Text:A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below: Depth (m) Cone resistance, 9c (MN/m²) 2.0 3.5 5.0 2.67 3.8 4.69 6.5 8.0 8.78 11.75 The average unit weight of the sand is 16.5 kN/m³. Assume moderately compressible sand and hence Qc = Determine the relative density at each depth using the equation below. Яс 1 Dr = 305QOCR 1.8 Ра σ' 0 Pa 0.5 (Enter your answers to three significant figures.) Depth (m) Dr (%) 2.0 3.5 5.0 6.5 8.0 = 1.
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