The following table gives the variation of the field standard penetration number (№60) in a sand deposit: Depth (m) N60 1.5 6 3.0 12 4.5 15 6.0 20 7.5 9.0 18 26 The groundwater table is located at a depth of 12 m. The dry unit weight of sand from 0 to a depth of 12 m is 17.6 kN/m³. Assume the mean grain size (D50) of the sand deposit to be about 0.8 mm. Estimate the variation of the relative density with depth for sand. Use the equation Dr (%) = = N60 (0.23+0.06/D50) 1.7 1 9 σo/Pa 0.5 (100) (Enter your answers to three significant figures.) Depth (m) N60 Dr. (%) 1.5 6 3.0 12 4.5 15 6.0 20 7.5 18 9.0 26
The following table gives the variation of the field standard penetration number (№60) in a sand deposit: Depth (m) N60 1.5 6 3.0 12 4.5 15 6.0 20 7.5 9.0 18 26 The groundwater table is located at a depth of 12 m. The dry unit weight of sand from 0 to a depth of 12 m is 17.6 kN/m³. Assume the mean grain size (D50) of the sand deposit to be about 0.8 mm. Estimate the variation of the relative density with depth for sand. Use the equation Dr (%) = = N60 (0.23+0.06/D50) 1.7 1 9 σo/Pa 0.5 (100) (Enter your answers to three significant figures.) Depth (m) N60 Dr. (%) 1.5 6 3.0 12 4.5 15 6.0 20 7.5 18 9.0 26
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
The following table gives the variation of the field standard penetration number in a sand deposit:
The groundwater table is located at a depth of 12 . The dry unit weight of sand from 0 to a depth of 12 is 17.6 . Assume the mean grain size of the sand deposit to be about 0.8 . Estimate the variation of the relative density with depth for sand. Use the equation
(Enter your answers to three significant figures.)

Transcribed Image Text:The following table gives the variation of the field standard penetration number (№60) in a sand deposit:
Depth (m) N60
1.5
6
3.0
12
4.5
15
6.0
20
7.5
9.0
18
26
The groundwater table is located at a depth of 12 m. The dry unit weight of sand from 0 to a depth of 12 m is 17.6 kN/m³. Assume the mean grain size (D50) of the sand deposit to be about 0.8 mm. Estimate the variation of the relative density with depth for
sand. Use the equation
Dr (%) =
=
N60 (0.23+0.06/D50) 1.7 1
9
σo/Pa
0.5
(100)
(Enter your answers to three significant figures.)
Depth (m) N60
Dr. (%)
1.5
6
3.0
12
4.5
15
6.0
20
7.5
18
9.0
26
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