Following is the variation of the field standard penetration number (N60) in a sand deposit: Depth (m) N60 1.5 6 3 7 4.5 9 6 7 7.5 9 10 12 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m³, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Using the equation Dr = { N60 [17+24(o/Pa)] 0.5 determine the average relative density of sand. (Enter your answer to three significant figures.) Average D, = %

Following is the variation of the field standard penetration number (N60) in a sand deposit: Depth (m) N60 1.5 6 3 7 4.5 9 6 7 7.5 9 10 12 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m³, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Using the equation Dr = { N60 [17+24(o/Pa)] 0.5 determine the average relative density of sand. (Enter your answer to three significant figures.) Average D, = %

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter2: Geotechnical Properties Of Soil

Section: Chapter Questions

Problem 2.27P

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Refer to Problem 3.5. Using Eq. (3.22), determine the averagerelative density of the sand.
Following is the variation of the field standard penetration number in a sand deposit: The groundwater table is located at a depth of 6 . Given: the dry unit weight of sand from 0 to a depth of 6 is 16 , and the saturated unit weight of sand for depth 6 to 12 is 22.2 . Estimate an average peak soil friction angle. Use the equation (Enter your answer to three significant figures.)
Following is the variation of the field standard penetration number () in a sand deposit: 1.5 6 3 8 4.5 9 6 8 7.5 13 9 14 The groundwater table is located at a depth of 6 . Given: the dry unit weight of sand from 0 to a depth of 6 is 19 , and the saturated unit weight of sand for depth 6 to 12 is 21.2 . Use the relationship given in the equation to calculate the corrected penetration numbers. (Round your answers to the nearest whole number.) 1.5 6 3 8 4.5 9 6 8 7.5 13 9 14
The following table gives the variation of the field standard penetration number in a sand deposit: The groundwater table is located at a depth of 12 . The dry unit weight of sand from 0 to a depth of 12 is 17.6 . Assume the mean grain size of the sand deposit to be about 0.8 . Estimate the variation of the relative density with depth for sand. Use the equation (Enter your answers to three significant figures.)
The standard penetration test results of a sand deposit at a certain site are given below in tabular form. The groundwater table in located at a depth of 2 m below the ground surface. The dry and saturated unit weights of sand are 17 kN/m³ and 19.0 kN/m', respectively. For an expected 10.8 earthquake magnitude M = 6 and maximum acceleration amax = 0.1 g, will liquefaction occur? Depth (m) NF (blows/30 cm) 1.5 8 3.0 7 4.5 12 6.0 15 7.5 17 9.0 17
21 The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 37 cm Length of sample = 92 cm Constant head difference = 78 cm Time of collection = 337 secs Weight of water collected = 375 grams Find the seepage velocity in cm/min. if the void ratio is 0.6. Round off to four decimal places.
A cone penetration test result of a deposit of normally consolidated dry sand are given below. Estimate the drained friction angle of the sand using Kulhawy and Mayne's equation. The unit weight of the sand is 100 pcf. Depth ft 5.0 10.0 15.0 20.0 25.0 30.0 45 38 42 40 Tip resistance of cone, qc psi 300 600 800 1200 1400 1800
Determine the relative density at each depth using attached equation. Assume moderately compressible sand and hence Qc = 1.
Determine the relative density at each depth using attached equation. Assume moderately compressible sand and hence Qc = 1.
P-1 A soil profile is shown in Figure along with the standard penetration numbers in the clay layer. Use provided equations to Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m N60 Ysat = 19 kN/m³ determine the variation of 1.5 m • 8 Cu and OCR and preconsolidation pressure o', with depth. What is the average value of c, and OCR? Clay 1.5 m Ysat = 16.8 kN/m³ * A•8 1.5 m • 9 1.5 m 10 Sand 0.689 0.29N0.72 Pa Си N60 OCR = 0.193 o = 0.47NPa %3D %3D Shahid Chamran University of Abvaz 1 ר ר ררפ
Question 16 The results of a constant head permeability test for a fine sand are as follows Diameter of the sample = 33 cm Length of sample 55 cm Constant head difference =74 cm Time of collection 580 secs Weight of water collected = 382 grams Find the seepage velocity in cm/min. if the void ratio is 0 38. Round off to four decimal places. SUS WE R