Equation (3.30) Following is the variation of the field standard penetration number (N) in a sand deposit: 70.34 6' = tan Depth (m) 12.2 + 20.3 1.5 6. 8 4.5 6. 8. 7.9 13 9 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.30) to calculate the corrected penetration numbers.
Equation (3.30) Following is the variation of the field standard penetration number (N) in a sand deposit: 70.34 6' = tan Depth (m) 12.2 + 20.3 1.5 6. 8 4.5 6. 8. 7.9 13 9 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.30) to calculate the corrected penetration numbers.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Refer to Problem 3.5. Using Eq. (3.22), determine the average
relative density of the sand.

Transcribed Image Text:Equation
(3.30)
Following is the variation of the field standard penetration
number (N) in a sand deposit:
70.34
6' = tan
Depth (m)
12.2 + 20.3
1.5
6.
8
4.5
6.
8.
7.9
13
9
14
The groundwater table is located at a depth of 6 m. Given:
the dry unit weight of sand from 0 to a depth of 6 m is
18 kN/m, and the saturated unit weight of sand for depth
6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq.
(3.30) to calculate the corrected penetration numbers.
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