1. How deep below the water surface is the bottom of the caisson when the water level gas risen 1.5 m inside?2. Compute the volume of air trapped inside the caisson.3. Compute the gauge pressure of the air trapped inside the caisson. Situation: The diving bell has a shape of a frustum of cone (circular) with a closed flattop and open bottom. It is lowered from the outside air into saltwater in anupright position. Ysaltwater = 10.2 kN/m³h1.5 mclosed top-2 m4 m4m

Volume of empty caisson (frustum) : V1=πh/3(R2+r2+Rr)V1=π×3/3×(22+1.52+2×1.5)V1=29.0597…

Situation: The diving bell has a shape of a frustum of cone (circular) with a closed flat top and open bottom. It is lowered from the outside air into saltwater in an upright position. Ysaltwater = 10.2 kN/m³ h 1.5 m closed top- 2 m 4 m 4m

Situation: The diving bell has a shape of a frustum of cone (circular) with a closed flat top and open bottom. It is lowered from the outside air into saltwater in an upright position. Ysaltwater = 10.2 kN/m³ h 1.5 m closed top- 2 m 4 m 4m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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