FeedbackYou have not correctly calculated the concentration of added Fab at which half ofthe lysozyme will be bound to the Fab.The dissociation constant (K) is the equilibrium constant for the dissociation of areceptor and ligand: RL = R + L. In this case, lysozyme is the receptor and theFab fragment is the receptor.Ka is given by the equation:[R][L][RL]Kd ==Under these conditions, half of the ligand is bound and half is unbound, so[L] = [RL]. Making this substitution for [L] in the equation for Ka gives you:Ka=[R][RL][RL]= = [R]However, you must determine the total receptor concentration (Rtotal), which is thesum of free receptor and receptor bound to ligand.Rtotal = [R] + [RL]Because half of the ligand is bound and half is unbound in this case, [RL] is equalto one-half of Ltotal. In this case, Ltotal the concentration of lysozyme inthe solution.X An Fab fragment binds to lysozyme with a dissociation constant of Ka =10-11 M. A 1 nM (10-9 M) solution of lysozyme istreated with increasing concentrations of the Fab fragment. At what concentration of added Fab will half of the lysozyme bebound to the Fab?[Fab]9.9IncorrectnM

We are given the binding kinetics between lysozyme (receptor) and Fab fragment (ligand).

Answered: = An Fab fragment binds to lysozyme…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

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= An Fab fragment binds to lysozyme with a dissociation constant of Ka 10-11 M. A 1 nM (10-9 M) solution of lysozyme is treated with increasing concentrations of the Fab fragment. At what concentration of added Fab will half of the lysozyme be bound to the Fab?