Absorbance at 210 nm →→ Thiourea (unretained) t = 41.7 min H₂N S NH2 188.1 D min D D D 4 5 D W1/2= 1.01 min 2 Ал At= 1.01 min 185 190 195 Time (min) 5 4 100 200 Time (min) D 300 CD3 CD3 CH3 7 8 D
Absorbance at 210 nm →→ Thiourea (unretained) t = 41.7 min H₂N S NH2 188.1 D min D D D 4 5 D W1/2= 1.01 min 2 Ал At= 1.01 min 185 190 195 Time (min) 5 4 100 200 Time (min) D 300 CD3 CD3 CH3 7 8 D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- The following is an HPLC separation of deuterated benzenes on a C18 column that 440 cm long. The mobile phase was 30% acetonitrile:70% water at 30oC.
- What is the mobile phase velocity?
- Find the retention factor k' for C6D6.
- Find the plate number and plate height for C6D6..
- Assuming that the peak widths for C6H5D and C6H6 are the same as that of C6D6., find the resolution for C6H5D and C6H6.
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Transcribed Image Text:Absorbance at 210 nm →→
Thiourea
(unretained)
t = 41.7 min
H₂N
S
NH2
188.1
D
min
D
D
D
4
5
D
W1/2=
1.01
min
2
Ал
At=
1.01
min
185
190
195
Time (min)
5
4
100
200
Time (min)
D
300
CD3
CD3 CH3
7
8
D
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