A) Is this reaction ( in picture provided) in equilibrium? B) If it is not then ,what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 15.04µM and the concentration of Glucose-6-phosphate is 1.62 mM? Answer in Joules. Round to the correct number of significant figures.
A) Is this reaction ( in picture provided) in equilibrium?
B) If it is not then ,what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 15.04µM and the concentration of Glucose-6-phosphate is 1.62 mM? Answer in Joules. Round to the correct number of significant figures.
(There are 103 µM in 1mM.)
Thank you so Much!!!


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You have been the only one who has been able to this. It has three other parts as well,
A) Which Enzyme Catalyzes this reaction?
choices are in image provided.
B) What is ∆G°' for this reaction? Answer in Joules. K' = 19
C)
If the reaction is not at equilibrium, what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 15.04µM and the concentration of Glucose-6-phosphate is 1.62 mM? Answer in Joules. Pay attention to units. Round to the correct number of significant figures.
There are 103 µM in 1mM.
Thank you and you are the winner for Genius of the day!!

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