A given enzyme is able to utilize five different substrates. The Km's ha measured for each substrate. Which substrate is most likely the bioch relevant one in the cell? In other words, which one is most likely the p vivo substrate for this enzyme? (Choose the one best answer). Substrate 1 with KM= 4.7 × 10-1 M. Substrate 2 with KM = 1.5 × 10-² M. Substrate 3 with KM = 1.5 x 10-8 M. Substrate 4 with KM= 4.7 × 10-3 M Substrate 5 with KM = 4.7 × 10-5 M
A given enzyme is able to utilize five different substrates. The Km's ha measured for each substrate. Which substrate is most likely the bioch relevant one in the cell? In other words, which one is most likely the p vivo substrate for this enzyme? (Choose the one best answer). Substrate 1 with KM= 4.7 × 10-1 M. Substrate 2 with KM = 1.5 × 10-² M. Substrate 3 with KM = 1.5 x 10-8 M. Substrate 4 with KM= 4.7 × 10-3 M Substrate 5 with KM = 4.7 × 10-5 M
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Question
![### Determining the Biochemically Relevant Substrate for an Enzyme
A given enzyme is able to utilize five different substrates. The KM values have been measured for each substrate. Which substrate is most likely the biochemically relevant one in the cell? In other words, which one is most likely the predominant in vivo substrate for this enzyme? (Choose the one best answer).
- **Substrate 1 with KM = 4.7 × 10^-1 M**
- **Substrate 2 with KM = 1.5 × 10^-2 M**
- **Substrate 3 with KM = 1.5 × 10^-8 M**
- **Substrate 4 with KM = 4.7 × 10^-3 M**
- **Substrate 5 with KM = 4.7 × 10^-5 M**
### Explanation
The Michaelis constant (KM) is a crucial parameter in enzyme kinetics that provides insight into the enzyme's affinity for a particular substrate. A lower KM value indicates a higher affinity, suggesting that the enzyme binds more readily to the substrate at lower concentrations. Therefore, the substrate with the lowest KM value would typically be the predominant in vivo substrate, as the enzyme will preferentially utilize this substrate at physiological concentrations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07b00a25-4bbc-4603-8563-821c16d74641%2F4e8a5538-e5d6-4410-8aad-617d6372c8a2%2Fxmvh4u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determining the Biochemically Relevant Substrate for an Enzyme
A given enzyme is able to utilize five different substrates. The KM values have been measured for each substrate. Which substrate is most likely the biochemically relevant one in the cell? In other words, which one is most likely the predominant in vivo substrate for this enzyme? (Choose the one best answer).
- **Substrate 1 with KM = 4.7 × 10^-1 M**
- **Substrate 2 with KM = 1.5 × 10^-2 M**
- **Substrate 3 with KM = 1.5 × 10^-8 M**
- **Substrate 4 with KM = 4.7 × 10^-3 M**
- **Substrate 5 with KM = 4.7 × 10^-5 M**
### Explanation
The Michaelis constant (KM) is a crucial parameter in enzyme kinetics that provides insight into the enzyme's affinity for a particular substrate. A lower KM value indicates a higher affinity, suggesting that the enzyme binds more readily to the substrate at lower concentrations. Therefore, the substrate with the lowest KM value would typically be the predominant in vivo substrate, as the enzyme will preferentially utilize this substrate at physiological concentrations.
![### True Statements About the Citric Acid (TCA) Cycle:
*(Choose all correct answers)*
- ☐ Decarboxylation reactions are part of the citric acid cycle.
- ☐ Reduced coenzymes NADH and FADH2 are produced as products of the citric acid cycle.
- ☐ This is an aerobic pathway.
- ☐ The major products of the citric acid cycle are NAD+, FAD, and ATP.
- ☐ The pathway occurs in the cytosol of eukaryotic cells.
- ☐ The pathway occurs in the mitochondrial matrix of eukaryotic cells.
When explaining the citric acid cycle or Tricarboxylic Acid (TCA) cycle, it may be essential to note the importance of each statement. This would include elaborating on key concepts such as:
1. **Decarboxylation Reactions:** Types of reactions involved in the cycle.
2. **Reduced Coenzymes:** The role and importance of NADH and FADH2.
3. **Aerobic Pathway:** Why oxygen is necessary for the process.
4. **Major Products:** Understanding all the molecules produced and their significance.
5. **Cellular Location:** Differentiating where in the cell this process occurs, especially between eukaryotic and prokaryotic cells.
Any student studying cellular respiration or related topics would benefit from a deeper dive into each of these aspects to thoroughly comprehend the complexity and functionality of the TCA cycle.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07b00a25-4bbc-4603-8563-821c16d74641%2F4e8a5538-e5d6-4410-8aad-617d6372c8a2%2Frxvcs7q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### True Statements About the Citric Acid (TCA) Cycle:
*(Choose all correct answers)*
- ☐ Decarboxylation reactions are part of the citric acid cycle.
- ☐ Reduced coenzymes NADH and FADH2 are produced as products of the citric acid cycle.
- ☐ This is an aerobic pathway.
- ☐ The major products of the citric acid cycle are NAD+, FAD, and ATP.
- ☐ The pathway occurs in the cytosol of eukaryotic cells.
- ☐ The pathway occurs in the mitochondrial matrix of eukaryotic cells.
When explaining the citric acid cycle or Tricarboxylic Acid (TCA) cycle, it may be essential to note the importance of each statement. This would include elaborating on key concepts such as:
1. **Decarboxylation Reactions:** Types of reactions involved in the cycle.
2. **Reduced Coenzymes:** The role and importance of NADH and FADH2.
3. **Aerobic Pathway:** Why oxygen is necessary for the process.
4. **Major Products:** Understanding all the molecules produced and their significance.
5. **Cellular Location:** Differentiating where in the cell this process occurs, especially between eukaryotic and prokaryotic cells.
Any student studying cellular respiration or related topics would benefit from a deeper dive into each of these aspects to thoroughly comprehend the complexity and functionality of the TCA cycle.
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