Enzyme X has a Km of 2 µM and a kcat of 104 s1. In the presence of an inhibitor, Kmincreases to 4 µM but kcat doesn't change.Is the inhibitor competitive, uncompetitive, or mixed? And what are the value(s) of aand/or a'? Choose N/A if not applicable.Inhibitor =[ Select ][ Select ]a =a'? = [ Select]

Enzymes are protein molecules that speed up the reactions by decreasing the activation energy.…

Answered: Enzyme X has a Km of 2 µM and a kcat of…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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☐ Consider the Lineweaver-Burk graph below. The "+ inhibitor" and "no inhibitor present" have the same y intercept. Which of the following accurately describe the effects of the inhibitor on the enzyme's kinetics? (Pick two.) + inhibitor 1/Vo -No inhibitor present 1/[S] The inhibitor doesn't change the Vmax The inhibitor decreases the Vmax The inhibitor increases the Km The inhibitor doesn't change the Km The inhibitor decreases the Km
what concentration of a competitive inhibitor is required to yield 60% inhibition of an enzyme at a substance concentration of 1.0x10^-4 M. The Km for the enzyme is 22 uM and the Ki for the inhibitor is 59 uM. To what concentration must the substrate be increased to reestablish velocity at the uninhibited value?
In pure noncompetitive inhibition: a. Where on the enzyme does the inhibitor bind? b. Does the inhibitor bind to E, ES or both? c. What is the effect of I on Vmax? d. What is the effect of I on Km?
(i) Which graph indicates an enzymatic reaction without inhibitor?(ii) Which type of inhibitor is it? Briefly explain.(iii) Which graph indicates the highest concentration of inhibitor?(iv) Calculate the Vmax and Km of the graph showing an enzymatic reaction with the lowest concentration of inhibitor. Show the steps of calculation and unit in your answers. Keep 2 decimal places in your answers.
-Inhibitor +Inhibitor [S] (mM) V0&νβσπ;(μmol/sec). νο&νβσπ: &ν βσπ (μmol/sec) 0.0001 33 17 0.0005 71 50 0.001 83 67 0.005 96 91 0.01 98 95 What is the Vmax of this enzyme WITH iinhibitor?
The Lineweaver-Burke plot was originally developed in order to "linearize" the data obtained from enzyme kinetics experiments, in order to facilitate the determination of kinetic parameters. Why is it not considered to be an accurate method for this purpose? It is very difficult to draw a straight line on a computer. It is very difficult to calculate the variables required for the "x" and "y" axis. It is more accurate to use the standard "V versus [S]" plot to determine Vmax and KM- The plot weights the least accurate data points the most heavily. It is no longer considered to be acceptable to extrapolate from known data.
The 2 eynzymes are affected by a substrate. Choose all correct answers.
you are trying to come up with a drug to inhibit the activity of an enzyme thuogth to have a role in a liver disease. in the lab the enzyme was shown to have a Km of 1x10-6 M and Vmax of 0.1 micromoles/min.mg measruing at room temperature. you developed a mixed non-competitve inhibitor with a ki=0.4x10-6M and a Ki` pf 0/2 x 10-5 What will be the apparent Km in the presence of 1.0x10-6 M?
How can you find Kcat if you are only given Vmax, Km and [E] ? I tried using Kcat=Vmax/[E] but that didn't work. How do you know if [E] is the same as [E]total, and if it isn't how do you find it from this information: The Vmax for a particular enzyme is 10 nmols/L/s. The Km for its substrate is 5 microM. If the enzyme concentration is 10 nM, what is the kcat? a.80 nmoles/L/s b.8000 nmoles/L/s c.2 nmoles/L/s d.50 nmoles/L/s
The following data was obtained during kinetic analysis of an enzyme with and without an inhibitor. Substrate concentration (mM) Reaction rate without inhibitor (µM/s) Reaction rate with inhibitor (µM/s) 10 28 12 20 50 23 40 83 42 60 107 58 100 139 83 200 179 125 300 197 150 400 209 167 560 227 197 How do you calculate the KM for the enzyme in the absence of an inhibitor. And how do you calculate kcat with the given enzymatic concentration of 5 µM.
In a uni uni enzyme reaction, what is the substrate concentration relative to Km when anenzyme operates at 0.95 * V. What about 0.99 * V?
At what substrate concentration would an enzyme with a Km of 0.005M operate at one quarter of its Vmax? What would be the Km for an enzyme if it is operating at 90% of its Vmax when the substrate concentration is 0.01M

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