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A genetic experiment involving peas yielded one sample of offspring consisting of 442 green peas and 149 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 269% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.26 О в. Но: ра0.26 H:p<0.26 H:p<0.26 OC. Ho: p#0.26 O D. Ho: p=0.26 H:p>0.26 H:p20.26 OF. Ho: p=0.26 O E. Ho: pz0.26 H:p=0.26 H,:p>0.26 What is the test statistic? (Round to two decimal places as needed.) What is the P.value? P-value (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.

A genetic experiment involving peas yielded one sample of offspring consisting of 442 green peas and 149 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 269% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.26 О в. Но: ра0.26 H:p<0.26 H:p<0.26 OC. Ho: p#0.26 O D. Ho: p=0.26 H:p>0.26 H:p20.26 OF. Ho: p=0.26 O E. Ho: pz0.26 H:p=0.26 H,:p>0.26 What is the test statistic? (Round to two decimal places as needed.) What is the P.value? P-value (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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A genetic experiment involving peas yielded one sample of offspring consisting of 442 green peas and 149 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.26 О В. Но: ра0.26 H1: p<0.26 H:p<0.26 OC. Ho: p#0.26 OD. Ho: p=0.26 H1: p>0.26 H1: p 0.26 OF. Ho: p=0.26 H: p>0.26 O E. Hp: p#0.26 H1: p= 0.26 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. O C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 442 green peas and 149 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.26 О В. Но: ра0.26 H1: p<0.26 H:p<0.26 OC. Ho: p#0.26 OD. Ho: p=0.26 H1: p>0.26 H1: p 0.26 OF. Ho: p=0.26 H: p>0.26 O E. Hp: p#0.26 H1: p= 0.26 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. O C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. O C. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
Transcribed Image Text:What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. O C. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
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X=149

n=442+149=591

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