A genetic experiment involving peas yielded one sample of offspring consisting of 438 green peas and 142 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis and final conclusion that addresses the original claim. Use the Pvalue method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? ⧠ A. ?0: ? ≠ 0.26 ?1: ? > 0.26 ⧠ B. ?0: ? = 0.26 ?1: ? < 0.26 ⧠ C. ?0: ? ≠ 0.26 ?1: ? < 0.26 ⧠ D. ?0: ? = 0.26 ?1: ? > 0.26 ⧠ E. ?0: ? = 0.26 ?1: ? ≠ 0.26 ⧠ F. ?0: ? ≠ 0.26 ?1: ? = 0.26 What is the test statistic? z = ______________________________ What is the P-value? P-value = ____________________________ What is the conclusion about the null hypothesis? ⧠ A. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. ⧠ B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. ⧠ C. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. ⧠ D. Reject the null hypothesis because the P-value is greater than the significance level, α. What is the final conclusion? ⧠ A. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. ⧠ B. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. ⧠ C. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. ⧠ D. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 438 green peas and 142 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis and final conclusion that addresses the original claim. Use the Pvalue method and the
What are the null and alternative hypotheses?
⧠ A. ?0: ? ≠ 0.26 ?1: ? > 0.26
⧠ B. ?0: ? = 0.26 ?1: ? < 0.26
⧠ C. ?0: ? ≠ 0.26 ?1: ? < 0.26
⧠ D. ?0: ? = 0.26 ?1: ? > 0.26
⧠ E. ?0: ? = 0.26 ?1: ? ≠ 0.26
⧠ F. ?0: ? ≠ 0.26 ?1: ? = 0.26
What is the test statistic? z = ______________________________
What is the P-value? P-value = ____________________________
What is the conclusion about the null hypothesis?
⧠ A. Reject the null hypothesis because the P-value is less than or equal to the significance level, α.
⧠ B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α.
⧠ C. Fail to reject the null hypothesis because the P-value is greater than the significance level, α.
⧠ D. Reject the null hypothesis because the P-value is greater than the significance level, α.
What is the final conclusion?
⧠ A. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
⧠ B. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
⧠ C. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
⧠ D. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
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