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Fundamentals Of Analytical Chemistry

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.3QAP

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Please don't use Ai solution

- A 25.00 mL sample containing an unknown amount of A13+ and Pb2+ required 20.86 mL of 0.04047 M EDTA to reach the end
point. A 50.00 mL sample of the unknown was then treated with F to mask the Al3+. To the 50.00 mL sample, 25.00 mL of
0.04047 M EDTA was added. The excess EDTA was then titrated with 0.02476 M Mn2+. A total of 10.4 mL was required to
reach the methylthymol blue end point. Determine pA13+ and pPb2+ in the unknown sample.
PAI³+
2.44
Incorrect Answer
pPb2+
1.82
=
Correct Answer

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A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 20.51 mL of 0.04633 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al³+. To the 50.00 mL sample, 25.00 mL of 0.04633 M EDTA was added. The excess EDTA was then titrated with 0.02353 M Mn²+. A total of 14.2 mL was required to reach the methylthymol blue end point. Determine pAl3+ and pPb2+ in the unknown sample. PA3+ ; pPb²+ II
A 25.00 mL sample containing an unknown amount of Al³ + and Pb² + required 15.73 mL of 0.05631 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the A1³ +. To the 50.00 mL sample, 25.00 mL of 0.05631 M EDTA was added. The excess EDTA was then titrated with 0.02203 M Mn² +. A total of 25.9 mL was required to reach the methylthymol blue end point. Determine pAl³ + and pPb² + in the unknown sample.
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Macmillan Learning A 25.00 mL sample containing an unknown amount of Al³+and Pb² +required 15.54 mL of 0.05734 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al³+. To the 50.00 mL sample, 25.00 mL of 0.05734 M EDTA was added. The excess EDTA was then titrated with 0.02256 M Mn² +. A total of 25.7 mL was required to reach the methylthymol blue end point. Determine pAl³+ and pPb²+ in the unknown sample. PA1³ + = pPb²+ =
A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back-titrated, requiring 2.37 mL of 0.04615 M Mg2+. What was the concentration of Fe3+ in the original solution in ppm Fe3+?
25.0 mL of an unknown Ni2+ solution was treated with 25.00 mL of 0.05283 M Na2EDTA. The pH of the solution was buffered to 5.5 and then back-titrated with 17.61 mL of 0.02299 M Zn2+. What was the unknown Ni2+ M?
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