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Fundamentals Of Analytical Chemistry

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.3QAP

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Please don't use Ai solution

- A 25.00 mL sample containing an unknown amount of A13+ and Pb2+ required 20.86 mL of 0.04047 M EDTA to reach the end
point. A 50.00 mL sample of the unknown was then treated with F to mask the Al3+. To the 50.00 mL sample, 25.00 mL of
0.04047 M EDTA was added. The excess EDTA was then titrated with 0.02476 M Mn2+. A total of 10.4 mL was required to
reach the methylthymol blue end point. Determine pA13+ and pPb2+ in the unknown sample.
PAI³+
2.44
Incorrect Answer
pPb2+
1.82
=
Correct Answer

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A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 20.51 mL of 0.04633 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al³+. To the 50.00 mL sample, 25.00 mL of 0.04633 M EDTA was added. The excess EDTA was then titrated with 0.02353 M Mn²+. A total of 14.2 mL was required to reach the methylthymol blue end point. Determine pAl3+ and pPb2+ in the unknown sample. PA3+ ; pPb²+ II
A 25.00 mL sample containing an unknown amount of Al³ + and Pb² + required 15.73 mL of 0.05631 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the A1³ +. To the 50.00 mL sample, 25.00 mL of 0.05631 M EDTA was added. The excess EDTA was then titrated with 0.02203 M Mn² +. A total of 25.9 mL was required to reach the methylthymol blue end point. Determine pAl³ + and pPb² + in the unknown sample.
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Macmillan Learning A 25.00 mL sample containing an unknown amount of Al³+and Pb² +required 15.54 mL of 0.05734 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al³+. To the 50.00 mL sample, 25.00 mL of 0.05734 M EDTA was added. The excess EDTA was then titrated with 0.02256 M Mn² +. A total of 25.7 mL was required to reach the methylthymol blue end point. Determine pAl³+ and pPb²+ in the unknown sample. PA1³ + = pPb²+ =
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A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back-titrated, requiring 2.37 mL of 0.04615 M Mg2+. What was the concentration of Fe3+ in the original solution in ppm Fe3+?
25.0 mL of an unknown Ni2+ solution was treated with 25.00 mL of 0.05283 M Na2EDTA. The pH of the solution was buffered to 5.5 and then back-titrated with 17.61 mL of 0.02299 M Zn2+. What was the unknown Ni2+ M?
100 mL of mineral water containing Mg2+ and Ca2+ is taken and titrated with 86.65 mL of 0.06120 M EDTA. NH4F was added to the second 100 mL portion taken from the mineral water to mask the magnesium in the sample as MgF2, and when this sample was titrated with the same EDTA solution, 38.56 mL was spent. Find the concentration of CaCO3 and MgCO3 in the sample in ppm.
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