E. Dilution GIVEN: FIND: APPROACH: 12.0 M HCl solution volume (mL) of solution required to make 100. mL of 2.35 M HCI Concentration = (Volume) Volume x Concentration; plus logic
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- 19)The equivalence point is defined as moles acid = moles base. So first, let's calculate the initial moles of base we used. molpase Mpase = Volsoiution Molarity base = 0.100 (M) Volume of solution= _50.00 mL Moles of base = _5.00 mmol So, we need 5.00 mmol of acid (titrant) to be delivered to the analyte. Since we know the molarity of the acid and moles of acid, we just need to solve for the volume of acid (titrant) to be added. molacid Voladded Macid Molarity acid = . 0.200 (M) Moles of acid = _5.00 (mmol) Volume of acid needed to reach equivalence point (mL)Having trouble with question 8a. Can you help?
- Please fill in blanks as shown on problem!!A cvg.cengagenow.com/ilrn/takeAssignment/takeCXPCompliantActivity.do?locator=Dassignment-take CHAPTER 4 - STOICHIOMETRY: QUANTITATIVE INFORMATION ABOUT CHEM OPrevious Page 5 of 9 Nex If you dilute 20.0 mL of 1.75 M hydrochloric acid to 700. mL, what is the molar concentration of the dilute acid? Molar concentration = nttps//als asp.cengage.info/als-asp/takeCan you explain how to solve 7
- 9:24 PM Mon Feb 21 * 65% A openstax.org Solute concentrations are often described with qualitative terms such as dilute (of relatively low concentration) and concentrated (of relatively high concentration). Concentrations may be quantitatively assessed using a wide variety of measurement units, each convenient for particular applications. Molarity (M) is a useful concentration unit for many applications in chemistry. Molarity is defined as the number of moles of solute in exactly 1 liter (1 L) of the solution: mol solute M = L solution EXAMPLE 3.14 Calculating Molar Concentrations A 355-mL soft drink sample contains 0.133 mol of sucrose (table sugar). What is the molar concentration of sucrose in the beverage? Solution Since the molar amount of solute and the volume of solution are both given, the molarity can be calculated using the definition of molarity. Per this definition, the solution volume must be converted from mL to L: mol solute 0.133 mol M = = 0.375 M L solution 355 mL × 1L…show full and complete procedure HANDWRITTEN onlyA 1.787 g sample containing some Fe2+ ion requires 31.50 ml of a 0.02188 M KMnO4solution to reach a pink endpoint. What is the percent by mass of Fe2+ in the sample?