E. Dilution GIVEN: FIND: APPROACH: 12.0 M HCl solution volume (mL) of solution required to make 100. mL of 2.35 M HCI Concentration = (Volume) Volume x Concentration; plus logic
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- Please fill in blanks as shown on problem!!Ignore my calculations that are already on there, but I'm struggling on this one and a step by step would really help me out. Thank you!port youl answers WILH igures. Pay attention to the units in the first column. Table 1 (Report) Tablet identity (brand) Tums Titration Tablet 1 Mass of tablet/sample (g) 1,3 11 9 Volume of HCl solution (mL) 10 ml Concentration of HCl solution (M) ).3M Amount HCI (mmol) Concentration of NaOH solution (M) 0.1M 30.3 ml. 48.7ml: Initial burette reading (mL) Final burette reading (mL) Volume of NaOH solution (mL) Amount NaOH (mmol) Amount CaCO3 (mmol)* Molar mass of CaCO3 (mg mmol-') Mass of CaCO3 in tablet/sample (mg) % mass CaCO3 in tablet (%) 500 Manufacturer's specification (mg) Cost of one bottle of tablets (S) Number of tablets per bottle
- Household bleach is an aqueous solution that contains 63.3 g of sodium hypochlorite, NaOCI, per 300 ml of solution. What is the molar concentration of sodium hypochlorite in bleach? B I of Paragraph + v Lato (Recom... 19px... vshow full and complete procedure HANDWRITTEN onlyHow am I supposed to calculate the mass of the final solution?