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Construct a curve for the titration of 50.00 mL of 0.1000 M PO43- with 0.1000 M HCI by calculating the PH at these specific volumes V (HCI)= 0 ml 2.V (HCI)= 25 ml 3.V (HCI)= 50 ml 4.V (HCI)= 75 ml 5.V (HCI)= 90 ml 6.V (HCI)= 100 ml 7.V (HCI) 150 ml 8.V (HCI)=200 ml

Construct a curve for the titration of 50.00 mL of 0.1000 M PO43- with 0.1000 M HCI by calculating the PH at these specific volumes V (HCI)= 0 ml 2.V (HCI)= 25 ml 3.V (HCI)= 50 ml 4.V (HCI)= 75 ml 5.V (HCI)= 90 ml 6.V (HCI)= 100 ml 7.V (HCI) 150 ml 8.V (HCI)=200 ml

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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Construct a curve for the titration of 50.00 mL of 0.1000 M PO43- with 0.1000 M HCI by calculating the PH at these specific volumes V (HCI)= 0 ml 2.V (HCI)= 25 ml 3.V (HCI)= 50 ml 4.V (HCI)= 75 ml 5.V (HCI)= 90 ml 6.V (HCI)= 100 ml 7.V (HCI) 150 ml 8.V (HCI)=200 ml
Transcribed Image Text:Construct a curve for the titration of 50.00 mL of 0.1000 M PO43- with 0.1000 M HCI by calculating the PH at these specific volumes V (HCI)= 0 ml 2.V (HCI)= 25 ml 3.V (HCI)= 50 ml 4.V (HCI)= 75 ml 5.V (HCI)= 90 ml 6.V (HCI)= 100 ml 7.V (HCI) 150 ml 8.V (HCI)=200 ml
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