E T The probability of a particle having energy E is P (E) = Ce¯ where k is Boltzmann's constant (1.38 * 10¯²³J/K). The system has three possible energy levels: o J/mol, 100 J/mol, and 250 J/mol. The temperature is 300 K. a) Convert each energy level to J / particle E b) Find C, the normalization constant. To do this, calculatee T those values (they are the unnormalized probabilities) to find q. for each energy. Add up Then solve for C = 1 / q. E. Ce E c) Calculate the average energy (expectation value) of a particle. That is, sum up E · Cе¯kT for each state. Recall that the expectation value of Energy = < E >= Σ (P · E) d) Plot P vs E at 300 K and 25 K. Assume C remains the same.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.26QE
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can you please help with part d

E
T
The probability of a particle having energy E is P (E) = Ce¯ where k is Boltzmann's
constant (1.38 * 10¯²³J/K). The system has three possible energy levels: o J/mol, 100 J/mol,
and 250 J/mol. The temperature is 300 K.
a) Convert each energy level to J / particle
E
b) Find C, the normalization constant. To do this, calculatee T
those values (they are the unnormalized probabilities) to find q.
for each energy. Add up
Then solve for C = 1 / q.
E. Ce
E
c) Calculate the average energy (expectation value) of a particle. That is, sum up E · Cе¯kT
for each state. Recall that the expectation value of Energy = < E >= Σ (P · E)
d) Plot P vs E at 300 K and 25 K. Assume C remains the same.
Transcribed Image Text:E T The probability of a particle having energy E is P (E) = Ce¯ where k is Boltzmann's constant (1.38 * 10¯²³J/K). The system has three possible energy levels: o J/mol, 100 J/mol, and 250 J/mol. The temperature is 300 K. a) Convert each energy level to J / particle E b) Find C, the normalization constant. To do this, calculatee T those values (they are the unnormalized probabilities) to find q. for each energy. Add up Then solve for C = 1 / q. E. Ce E c) Calculate the average energy (expectation value) of a particle. That is, sum up E · Cе¯kT for each state. Recall that the expectation value of Energy = < E >= Σ (P · E) d) Plot P vs E at 300 K and 25 K. Assume C remains the same.
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