72In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6961 subjects randomly selected from an online group involved with ears. There were 1306 surveys retumed. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-valuemethod and use the normal distribution as an approximation to the binomial distribution.Identify the null hypothesis and alternative hypothesis.OA H₂: p=0.2H₁: p<0.2OC. Ho: p*0.2H₁: p=0.2OE. Ho:p>0.2H₁: p=0.2The test statistic is z=(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)Because the P-value isless thanthe significance level,greater thanthe null hypothesis. There isrejectfail to rejectsufficientOB. Ho: p=0.2H₁: p=0.2insufficientOD. Ho: p=0.2H₁: p>0.2evidence to support the claim that the return rate is less than 20%.OF. Ho: p<0.2H₁: p=0.2This quest

Let p be the true proportion of the population that returns the survey. Then, under the null…

Answered: 72 In a study of cell phone usage and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a program designed to help patients stop smoking, 181 patients were given sustained care, and 84.5% of them were no longer smoking after one month. Use a 0.05 significance level to test the claim that 79% of patients stop smoking when given sustained care. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. identify the test statistic. identify the P-value.
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6999 subjects randomly selected from an online group involved with ears. There were 1310 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
When dragons on planet Pern lay eggs, the eggs are either green or yellow. The biologists have observed over the years that 18% of the eggs are yellow, and the rest green. Next spring the lead scientist has permission to randomly select 41 of the dragon eggs to incubate. Consider all the possible samples of 41 dragon eggs.What is the mean number of yellow eggs in samples of 41 eggs? (that is the same as asking for the expected value of the number of yellow eggs)(Give answer correct to at least one decimal place.)mean = What is the standard deviation in the number of yellow eggs in samples of size 41?(Give answer correct to at least one decimal place.)standard deviation = What is the variance in the number of yellow eggs in samples of size 41?(Remember to calculate the answer using at least 5 decimal places, then give answer correct to at least one decimal place.)variance =
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A genetic experiment involving peas yielded one sample of offspring consisting of 447 green peas and 124 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
In a study of cell phone usage and brain hemispheric dominance, an Intemet survey was e-mailed to 6992 subjects randomly selected from an online group involved with ears. There were 1294 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA Ho p0.2 H1 p 0.2 O c. Ho p# 0.2 D. Ho: p 0.2 H p 0.2 H1 p 0.2 OE. Ho p 0.2 O F. Ho p 0.2 H1 p>0.2 Hy:p<0.2 The test statistic is z (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the significance level, Because the P-value is the null hypothesis. There is evidence to support the claim that the return rate is less than 20%
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find test statistic AND p value
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6990 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0 01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal diştribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>02 H p=02 О В. Но р302 H p0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Because the P-value is the significance level,
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An apple juice producer buys all his apples from a conglomerate of apple growers in one northwest state. The amount of juice squeezed from each of these apples is approximately normally distributed with a mean of 2.06 ounces and a standard deviation of 0.16 ounce. What is the probability that a randomly selected apple will contain more than 2.35 ounces?
A genetic experiment involving peas yielded one sample of offspring consisting of 444 green peas and 126 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.23 O B. Ho: p=0.23 H₁: p>0.23 H₁: p=0.23 OC. Ho: p=0.23 O D. Ho: p=0.23 H₁: p0.23 H₁: p=0.23 What is the test statistic? Z= (Round to two decimal places as needed.) What is the P-value? P-value= (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because…

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