Answered: 7. Tropolone (A) is a molecule that… | bartleby

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter22: Organic And Biological Molecules

Section: Chapter Questions

Problem 118E

See similar textbooks

Related questions

Question

7. Tropolone (A) is a molecule that easily loses a proton (H+) to form a relatively stable
anion (B). In tropolone (A), the double and single bonds are clearly distinct from each
other and their bond lengths very greatly (alternating long, short, long, etc.). However,
in ion B, all of the carbon-carbon bonds are very similar. Explain.
A
OH
+H-
B

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Proteins are made of amino acids. Given below is the structure of an example of amino acid. What are the two functional groups found in all amino acids? H CH3 | T + H-N-C-C T H H O carboxylate group and methyl group O ammonium group and methyl group O methyl group and thiol group O aldehyde group and ketone group O ammonium group and carboxylate group O
4. Below are the structures of some medications. Circle and identify functional groups in the structures. H₂C H₂C core MDPV Mephedrone 'N H CH3 Cocaine CH3 CH3 Methylone CH3 Aom CH3 CH3 CH3 Amphetamine NH₂ но... HO HO LaH O ACO OH 10-deacetylbaccatin III
Match each molecule/ functional group below to its most distinguishing feature. + wax A. COOH B. four fused ring structures * triacylglycerol C. polar head + two non polar tails + fatty acid D. glycerol + 3 fatty acids + ester Е. С-ОН + alcohol F. long chain carbon + alcohol + steroid G. * glycerophospholipid || — С-0- + carboxylic acid H. long chain carbon ending in COOH
Please answer #7 and 8
3. Justify aromaticity (or lack thereof) in the biological molecules below. H2N NH2 H H `NH2 `NH2 N- NH N. `NH ADP ADP N. `NH2 H ОН ОН ОН ОН adenine guanine cytosine thymine NAD+ NADH H OH H3C. H3C. CH30. CH30 10 10 H3C 'N' N. H3C N. CH30 CH30 N' CH2 OH CH2 H H-C-OH H -OH- ubiquinone ubiquinol H-C-OH H- -он Н-С—он H Ċ-OH CH2 CH2 ADP ADP FAD FADH2
Hello I am stuck on this question, can I get help please? A CLEAR explanation with Drawings and the correct answer would be helpful. Thank you!
Q4 Label ALL the functional groups in the following structures. Provide as much information as possible about the functional groups (primary, secondary, tertiary, phenolic, allylic etc) но. Meo Capsaicin Citalopram но HO но HO. Atropine Prostaglandin D2
15. Identify the functional group(s) in each compound i CH3CH₂CCH3 2-butanone (a solvent for paints and lacquers) a) H₂NCH₂CH₂CH₂CH₂CHCOH Lysine NH₂ (one of the 20 amino acid building blocks of proteins) c) 9 i HOCCH₂CH₂CH₂CH₂COH Hexanedioic acid (the 2nd component of nylon-66) b) i HOCH₂CCH₂OH Dihydroxyacetone (a component of several artificial tanning lotions) d)
2. Consider the following organic molecules A-H. Many of them are natural products isolated from Nature. Please answer the following questions by writing the Letter pertaining to each molecule next to the question. -N- H;C "CO,H N. Но CH2 ČH3 B strychnine (a plant alkaloid) hirsutic acid A nepetalactone (essence of cutnip) (a fimgul metabolito) H- H. I CH,0 E helminthosporal (a imgal toxu) D progesterone F cantharidin (a progestin hommone) (am insect vesicant) Br NO2 Br CI G untenine C (E)-1,6-dibromo-2,7-dichloro-3,7-dimethyloct-3-ene (fom red algae) (4 sponge metabolite)
Convert the condensed structures below into line-angle structures. Please note that some of the structures have “branches,” and some might have double or triple bonds. Please be very careful that you do not miss any hydrogen, carbon, nitrogen, oxygen, or sulfur. a.(N≡C)2CHCH2CH(CH=CH2)CH2C≡CCH2CH=O b. CH3OCH2S-SCCl2CH2CH=NCH2CO2H
1. Explain the following - why stearic acid has higher melting point than decanoic acid. - why benzoic acid has higher melting point than stearic acid. - why salicylic acid has higher melting point than benzoic acid. - why octane has a higher melting point than isooctane. - why 2,2,3,3-tetramethylbutane has the highest melting point among the three isomers of C8H18.
1. Simple sugars are defined as polyhydroxy aldehydes/ketones. All carbons except one have an OH group. The remaining carbon has a double bond to oxygen, making it an aldehyde or ketone. For example, the Fisher projection of glucose looks like this: C H- H- -ОН НО -ОН -HO- CH2OH Because a simple sugar has both a carbonyl carbon and built-in nucleophiles, a reaction can occur within the molecule itself to create the hemi-acetal form of the sugar. Propose a mechanism for this reaction when it occurs in an aqueous solution. C -- CH2OH он в CH2OH HO- H H НО H. ОН Н and ОН Н HO- он Он а OH H H- ОН OH H ОН ČH2OH

SEE MORE QUESTIONS

Recommended textbooks for you

Chemistry

Chemistry

ISBN:

9781305957404

Author:

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:

Cengage Learning

Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach

Chemistry

ISBN:

9781305079243

Author:

Steven S. Zumdahl, Susan A. Zumdahl

Publisher:

Cengage Learning

Chemistry

Chemistry

ISBN:

9781133611097

Author:

Steven S. Zumdahl

Publisher:

Cengage Learning

Chemistry

Chemistry

ISBN:

9781305957404

Author:

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:

Cengage Learning

Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach

Chemistry

ISBN:

9781305079243

Author:

Steven S. Zumdahl, Susan A. Zumdahl

Publisher:

Cengage Learning

Chemistry

Chemistry

ISBN:

9781133611097

Author:

Steven S. Zumdahl

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS