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You have 150.0 mL of a 0.781 M solution of Ce(NO3)4. What mass (in grams) of Ce(NO3)4 would be required to make the solution?

You have 150.0 mL of a 0.781 M solution of Ce(NO3)4. What mass (in grams) of Ce(NO3)4 would be required to make the solution?

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter3: Molecules, Moles, And Chemical Equations
Section: Chapter Questions
Problem 3.103PAE: 3.103 What is the mass in grams of solute in 250.0 mL of a 0.0125 M solution of KMnO4?
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You have 150.0 mL of a 0.781 M solution of Ce(NO3)4. What mass (in grams) of Ce(NO3)4 would be required to make the solution?
Transcribed Image Text:You have 150.0 mL of a 0.781 M solution of Ce(NO3)4. What mass (in grams) of Ce(NO3)4 would be required to make the solution?
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