5. Which side of the equilibrium will the following reactions most like sit? Give a thoroug explanation for how you derived your answers. The cations are omitted for clarity. C points) O + HO + H₂O OH

Kafor acetic acid (HC2H3O2) at 25°C is 1.754105 . At 50°C, Kais 1.633105 . Assuming that H° and S° are not affected by a change in temperature, calculate S° for the ionization of acetic acid.

If you observe the following reaction at equilibrium, is it possible to tell whether the reaction stated with pure NO2 or with pure N2O4? 2NO2(g)N2O4(g)

How is the strength of an acid related to the position of its ionization equilibrium? Write the equations for the dissociation (ionization) of HCI, HNO3, and HClO4in water. Since all these acids are strong acids, what does this indicate about the basicity of the Cl-, NO3, and ClO4ions? Are aqueous solutions of NaCl, NaNO3, or NaClO4basic?

Consider citric acid, H3C6H5O7, added to many soft drinks. The equilibrium constants for its step-wise ionization areKa1=7.5104 ,Ka2=1.7105, andKa3=4.0107. Write the overall net ionic equation and calculate K for the complete ionization of citric acid.

What is the effect on the concentrations of NO2-, HNO2, and OH- when the following are added to a solution of KNO2 in water: (a) HCl. (b) HNO2. (c) NaOH. (d) NaCl. (e) KNO The equation for the equilibrium is: NO2(aq)+H2O(l)HNO2+OH(aq)

Consider the following reaction: CH₃COOH(aq) + H₂O(l) ⇌ CH₃COO⁻(aq) + H₃O⁺(aq). An increase in the pressure of the chamber where this reaction takes place will result in A) an increase in CH₃COOH. B) an increase in CH₃COO⁻. C) an increase in H₃O⁺. D) both (B) and (C). E) no change.

Given a solution of acetic acid, with equilibrium net ionic equation (so only showing the ions in the reaction and not the spectator ions): CH3COOH (aq) + H20 () CH3COO (aq) + H3O* (aq) Have 4 beakers with acetic acid. Each beaker gets one of the following four things added to it. Match each thing with how the equilibrium responds when the thing is added. Prompts Submitted Answers sodium acetate Choose a match calcium acetate nothing sodium chloride shifts left to make more reactants acetic acid shifts right then left then right then left... shifts right to make more products

The Ka for HClO is 3.0 x 10-8. Calculate [H+] at equilibrium if the initial [HClO] = 0.075M.

3. Write the equation for the equilibrium constant K. (like equation 2-24) for the following 2 eq reactions (values in table 2-3): a) H₂CO3 → HCO3 + H+ b) HCO3 → CO3² + H+