7. A two-layer high-voltage cable is given, insulated with the plastic PA 1-4 with the inner radius Rin = 30 mm, the required middle radius" Rb = ?" and the outer radius Rout = 80 mm. The second layer of insulation is XLPE with a With an applied voltage U = 500 kV between conductor and external sheet. Cable sheet is grounded. Length 1 = 1 m. relative permittivity of &2 = 2.5. required Rb Rin 30 mm Rout 80 mm Er E12 500 kv Figure 1. schematic of the insulation system of the cable in the electrostatic field a. Draw the electric field in the cable. Fig. 1. b. Show that the electric field strength in the cable can be calculated using the following equation: E U r. In(rout/rin) C. Calculate the middle radius Rb for the optimum case of maximum field strengths E1 and E2 in the cable. (Rb>=50 mm, alternative result) d. Draw the curve of the field graphically. (Diagram is given on next page) c. Show that the capacitance of the cable can be calculated using the following formula: C Tout Tin f. Calculate the capacity of the sub-sections and the total capacitance. g. Calculate the electric charge of the cable.

7. A two-layer high-voltage cable is given, insulated with the plastic PA 1-4 with the inner radius Rin = 30 mm, the required middle radius" Rb = ?" and the outer radius Rout = 80 mm. The second layer of insulation is XLPE with a With an applied voltage U = 500 kV between conductor and external sheet. Cable sheet is grounded. Length 1 = 1 m. relative permittivity of &2 = 2.5. required Rb Rin 30 mm Rout 80 mm Er E12 500 kv Figure 1. schematic of the insulation system of the cable in the electrostatic field a. Draw the electric field in the cable. Fig. 1. b. Show that the electric field strength in the cable can be calculated using the following equation: E U r. In(rout/rin) C. Calculate the middle radius Rb for the optimum case of maximum field strengths E1 and E2 in the cable. (Rb>=50 mm, alternative result) d. Draw the curve of the field graphically. (Diagram is given on next page) c. Show that the capacitance of the cable can be calculated using the following formula: C Tout Tin f. Calculate the capacity of the sub-sections and the total capacitance. g. Calculate the electric charge of the cable.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter4: Transmission Line Parameters

Section: Chapter Questions

Problem 4.1P: The Aluminum Electrical Conductor Handbook lists a dc resistance of 0.01558 ohm per 1000 ft at 20C...

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The Aluminum Electrical Conductor Handbook lists a dc resistance of 0.01558 ohm per 1000 ft at 20C and a 60-Hz resistance of 0.0956 ohm per mile at 50C for the all-aluminum Marigold conductor, which has 61 strands and whose size is 1113 kcmil. Assuming an increase in resistance of 2 for spiraling, calculate and verify the dc resistance. Then calculate the dc resistance at 50C, and determine the percentage increase due to skin effect.
A 30 kV single core cable has a conductor dimeter of 2 cm and a sheath of inside diameter 6 cm. Find the maximum (peak value) and minimum stress (peak value) in the insulation.
The diameter of an ACSR conductor is 1.1116 inches. The steel core has strands of diameters of 0.1291 inches each. If 54 Aluminum strands have the diameters of 0.1351 inches each, the number of Steel strands is: O A. 15 O B. None of choices are correct O C. 19 O D.7 O E. 27
The property of insulating material which makes the breakdown voltage high in a cable is ...... Good Mechanical strength O High conductivity O High dielectric strength O High insulation resistance
Explain the L di/dt voltage problem in conductors undergoing commutation.
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If the cross sectional area of a conductor is doubled, then the resistance of the conductor remains the same. becomes half of the initial value. becomes double the initial value. becomes four times the initial value.
E A 2-wire d.c. ring distributor is 400 m long and is fed at 240 V at point A. At point B, 150 m from A, a load of 150 A is taken and at C, 100 m from B, with load of 40 A and at D, 25m in the opposite direction from A, a load of 200 A is taken. If the resistance per 100 m of single conductor is 0.04 22, find: (i) Current in each section of distributor (ii) Voltage at points B, C and D.
A 2-wire d.c. ring distributor is 300 m long and is fed at 240 V at point A. At point B, 150 m from A, a load of 120 A is taken and at C, 100 m in the opposite direction, a load of 80 A is taken. If the resistance per 100 m of single conductor is 0.030. find: (i) current in each section of distributor (ii) voltage at points B and C.
H. W.: The cost of a 2-core feeder cable, including installation is (90 a + 20) per meter and the interest and depreciation charges are 10 per cent. The cable is 2 km in length and cost of energy is 4% per unit. The maximum current in the feeder is 250 A and the demand is such that the current copper loss is equivalent to what would be produced by the full flowing for 6 months. If the resistance of a conductor of 1 square cm and 1 km length is 0.173 Q, calculate the most economical cross-sectional area.
The diameter of an ACSR conductor is 1.162 inches. The steel core has 7 strands of diameter 0.1291 inches each. If Aluminum strands have the same diameter as that of a steel strand, the number of Aluminum strands is: O A. None of choices are correct O B. 36 O C. 74 O D. 54 O E. 45
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