H. W.: The cost of a 2-core feeder cable, including installation is (90 a + 20) per meter and the interest and depreciation charges are 10 per cent. The cable is 2 km in length and cost of energy is 4% per unit. The maximum current in the feeder is 250 A and the demand is such that the copper loss is equivalent to what would be produced by the full current flowing for 6 months. If the resistance of a conductor of 1 square cm and 1 km length is 0.173 Q, calculate the most economical cross-sectional area.

H. W.: The cost of a 2-core feeder cable, including installation is (90 a + 20) per meter and the interest and depreciation charges are 10 per cent. The cable is 2 km in length and cost of energy is 4% per unit. The maximum current in the feeder is 250 A and the demand is such that the copper loss is equivalent to what would be produced by the full current flowing for 6 months. If the resistance of a conductor of 1 square cm and 1 km length is 0.173 Q, calculate the most economical cross-sectional area.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Maximum power transfer theorem

A resistive load will consume maximum power from a network when the load resistance is equal to the resistance of the network as viewed from the open-circuit terminals, with all energy sources removed leaving only the internal resistances. Physicist Moritz von Jacobi introduced the maximum power transfer theorem in 1940. Therefore, this theorem is also known as Jacobi's law.

Question

100%

H. W.: The cost of a 2-core feeder cable, including installation is (90 a +
20) per meter and the interest and depreciation charges are 10 per cent.
The cable is 2 km in length and cost of energy is 4% per unit. The
maximum current in the feeder is 250 A and the demand is such that the
current
copper loss is equivalent to what would be produced by the full
flowing for 6 months. If the resistance of a conductor of 1 square cm and
1 km length is 0.173 Q, calculate the most economical cross-sectional
area.

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