Explain question 4 thoroughly. 4. Circle the stronger acid on salicylic acid and explain your reasoning0||C-OH.OHSalicylic acid

In salicylic acid, there are two functional groups with acidic protons: the carboxylic acid group…

Answered: 4. Circle the stronger acid on…

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter19: Biomedical Laboratory Instrumentation

Section: Chapter Questions

Problem 6Q

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27)
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At a pH of 7.40, the carbonic acid ratio is ________. a. 35:1 b. 4:1 c. 20:1 d. 3:1
Some undiluted acids are not as corrosive as when they are diluted with water. That is why lab workers are told to wipe off splashes with a towel before washing. Explain.
Some undiluted acids are not as corrosive as when they are diluted with water. That is why lab workers are told to wipe off acid splashes with a towel before washing skin. Explain.
9. Compare the pH of milk and vinegar, which one is more acidic? How much is the difference between pH of these two solutions? How much is the difference between the hydrogen ion [H+] concentrations of these two solutions? Show your work.
1. How many moles of acetate are there in a 200 mL 0.20 M acetate buffer pH 4.95? pKa = 4.76 2. In a solution of pH 4.76, containing both acetic acid and acetate, what can you say about the concentrations of acetic acid and acetate present?
1. Draw the predominant forms of glutamic acid with increasing pH. The pKas for the ionizable groups are amino terminus = 9.67, carboxy terminus = 2.19, and side chain carboxylic acid = 4.25. C D A Charge: Charge: Charge Charge Lowest pH Highest pH
Please answer 10
5 Justify your answer. Carbon dioxide (CO2) in the air dissolves in distilled water. The CO2 then reacts with water molecules to produce carbonic acid (H2CO3) as shown in the equation below. Would you expect the pH of distilled water to be 7, greater than 7, or less than 7? CO2 (g) + H2O (l) H2CO3 (aq)
Circle and name three polar functional

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4. Circle the stronger acid on salicylic acid and explain your reasoning 0 || C-OH .OH Salicylic acid