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4. (a) (b) (c) By using double integrals, find the volume bounded by x+y+z = 2 in the first octant. 2x+y+z=4, planes x = 0, y = 0 and z = 0. surfaces y = x², y + z = 4 and z = 0. 2 (d) cylinder y² + z² = 1, plane y = x and yz-plane in the first octant.

4. (a) (b) (c) By using double integrals, find the volume bounded by x+y+z = 2 in the first octant. 2x+y+z=4, planes x = 0, y = 0 and z = 0. surfaces y = x², y + z = 4 and z = 0. 2 (d) cylinder y² + z² = 1, plane y = x and yz-plane in the first octant.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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4. (a) (b) (c) By using double integrals, find the volume bounded by x+y+z = 2 in the first octant. 2x+y+z=4, planes x = 0, y = 0 and z = 0. surfaces y = x², y + z = 4 and z = 0. 2 (d) cylinder y² + z² = 1, plane y = x and yz-plane in the first octant.
Transcribed Image Text:4. (a) (b) (c) By using double integrals, find the volume bounded by x+y+z = 2 in the first octant. 2x+y+z=4, planes x = 0, y = 0 and z = 0. surfaces y = x², y + z = 4 and z = 0. 2 (d) cylinder y² + z² = 1, plane y = x and yz-plane in the first octant.
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