Please solve in detail to understand Problem 1:Ch4: Overcurrent ProtectionConsider the radial system shown below. Assume that relay R5 does not need any coordinationand that relay R1 is set to provide backup protection for relay R5. Minimum and Maximumfaults at each of the three buses are given below. Maximum load currents are given as well in busesB and C. All pickup taps are available and the relay characteristic is given at the end of the booklet.1. Find CT ratios associated to relays R1 and R5.2. Find the settings of the Time Delay OC relay R5.3. Find the settings of the Time Delay OC relay R1.4. Find the settings of the instantaneous relays at stations A and B. Discuss.A야BR1R3R5Line 1100ALine 2с100AMinimum4000 A3000 A2000 AFaultMaximum10,000 A6000 A4000 AFault

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Answered: Problem 1: Ch4: Overcurrent Protection…

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter14: Phase Failure Relays

Section: Chapter Questions

Problem 1SQ: What is the purpose of phase failure relays?

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(b) An 11 kV, 50 Hz radial system is shown in Figure 6. Assume a CO-7 overcurrent protective relay with characteristic given in Figure 7. By using different power factor for all loads (in the range of 0.8 - 0.9), design suitable relay settings (current tap setting, time dial setting) and coordination design to protect the system with time interval of 0.3 seconds. 3 2 1 11 kV C.T.R=400/5 C.T.R=200/5 C.T.R=200/5 Figure 6: Simple radial network Load at bus 3 :7 MW, Short circuit rating at bus 3 (Isc3) = 4kA : 3 MW, Short circuit rating at bus 2 (Isc2) = 3kA : 4 MW, Short circuit rating at bus 1 (Isc1) = 2kA %3D Load at bus 2 Load at bus 1 %3D Typical time curves type CO-7 over current relay 50–60 cycles Current tap settings: 4,5,6,7,8,10,12 amperes Time dial setting 10 1/2. 3 5 6 7 8 9 10 12 14 16 18 20 Current as a multiple of tap setting Figure 7: CO-7 Overcurrent Protective Relay Time vs Current Curve Operating time in seconds
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Problem 2 - A 1000 – MVA, 20 – kV, 60 – Hzthree-phase generator is connected through a 1000 – MVA, 20 – kVA/345 – kVYtransformer to a 345 – kVcircuit breaker and a 345 – kVtransmission line. The generator reactances are X = 0.15, Xa = 0.3, Xa = 1.4(pu) and its time constants are Ta = 0.05, Ta = 1.0, TA = 0.1(s). The transformer series reactance is 0.06pu; transformer losses and exciting currents are neglected. A three-phase bolted fault (solid 3-phase phase short circuit) occurs on the line side of the circuit breaker when the generator is operated at rated terminal voltage and at no-load. The breaker interrupts the fault 3 cycles after fault inception (neglect the effect of the transformer on generator time constants.) Determine the following (a) The subtransient current (p.u.) through the breaker (b) The sub-transient current (kA) through the breaker (c) The RMS ac (symmetric) fault current (p.u.) after 3 cycles
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