3. Consider the following steel shaft (E = 30x10" psi) 0.75d w=200 lb/in. 0.75d -5 15 in.- What is the diameter d so the deflection at the middle is not larger than 0.2 mm? Use Energy Methods.
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- For the vertical rod as shown, find the deflection at A and the stress distribution. Use E-100 MPa and weight per unit volume equal to 0.06 N/cm3. (Hint: Introduce weight contribution to the nodal loads and solve using two elements and four elements.) Comment on the stress distribution. a) Use 2 & 4 elements with linear shape functions. b) Use 2 elements with quadratic shape functions. 1.6m C A -Area - 2500 cm² 8 Area - 1500 cm²4) Find the deflection midway between the supports. 4 kN/m 5 kN 1m 2 kN.m 2m 2m 2m 2m 5 mm E=200 GPA 20 mm 50 mm Beam Cross-Section Ra=2.61kn Rb=14.39kn Solve it by using singularity functionsDo not give answer in image and hand writing
- a) A steel 4 X 4X 0.25-inch square tube (moment of inertia I = 8.215 inª) is used as a simply supported beam. A 100-pound weight is dropped from a height of 24 inches onto the beam at mid- span. Find the maximum stress in the beam. Use E = 29 X 106 psi. 8 ft k = 200 lb/in 100 lb 8 ft b) Instead of fixed supports, the beam is supported by springs at both ends. Find the maximum stress in the beam when the 100-pound weight is dropped from a height of 24 inches (same beam properties as in part a). 24 in 100 lb 8 ft 24 in 8 ft k = 200 lb/in2 thumbs up if u get it right make sure ur units for final answer match questions Use Castigliano's theorem to determine the magnitude of deflection at midspan for the solid steel shaft shown in the figure, where a = 3 in, b= 7 in, da = 1.125 in, db = 1.875 in, and w=160 lbf/in. da a → db W b A The magnitude of deflection at the mid-span of the beam is 0.016265 * in. 6. Simple supports-intermediate load a + ·1 F B da b с R₂ x R₁ = VAB = R₁ MAB = YAB = Fb 1 Увс = Fbx 1 Fbx 6EI1 Fa R₂ = 1 VBC-R₂ Fa MBC= -(1-x) 1 ; (x² + b² −1²) Fa (1-x) 6EI1 -(x² + a² - 21x) Page 1032Part A A simply supported shaft is shown in the figure below. Assume the following data: a = 16 in, b = 18 in, l = 20 in, P = 1000 lb, Tmin=0 lb-in, Tmax=2000 lb-in. The steel shaft diameter is 1.75 in. Determine the maximum deflection in bending of the shaft shown in the figure. Express your answer in inches to three significant figures. Enter positive value if the deflection is upward and negative value if the deflection is downward. Submit Previous Answers Request Answer Part B ΗΠΙΑΣΦΗ * Incorrect; Try Again; 4 attempts remaining vec Omaz = Submit bearings are self-aligning so act as simple supports Determine the magnitude of the maximum deflection in torsion of the shaft shown in the figure. Express your answer in degrees to three significant figures. ΑΣΦΗ ΠΕ vec Previous Answers Request Answer ? in ?
- 1- The shaft shown in the below Fig. consists of a 75-mm diameter aluminum segment rigidly joined to a 50-mm diameter steel segment. The ends of the shaft are attached to rigid supports. Calculate the maximum shear stress developed in each segment when the torque T = 1130 N.m. is applied. Use G = 28 GPa for aluminum and G = 83 GPa for steel. %3D %3D Aluminum Steel 75 mm diameter 50 mm diameter 1130 N.m Tal 1st 2 m 1 mThis is part of alarger super position problem and I was able to solve for a moment and a concentrated load but this distributed load is confusing me. E = 200 GPa I = 216*10^6 mm^4 w = 81 kN/m d = 1.5 m I ended up getting an answer near -12 mm of diflection but that is an incorrect according to the grader. What would the equation for the elastic curve of this problem be? What is its value at point B? thank you so much!The W250x22 cantilevered beam is made of A-36 steel and is subjected to the loading shown below. Suppose that P1-40kN and P2-12 kN. B P₁ 2 m- B A -2 m- a) Determine the displacement at B. Express answer to three significant figures and include appropriate units. Positive value if the deflection is upward and the negative value is if the deflection is downward. b) Determine the slope at B Express answer in radians to three significant figures. Positive value if the slope is counterclockwise and the negative value if the slope is clockwise.