29) Polyethylene can be obtained in two different forms. High-density polyethylene (0.94 g/cm3is a linear polymer. Low-density polyethylene (0.92 g/cm3) is a branched polymer with shortside-chains on 3% of the atoms along the polymer chain. What could be the reason of thechange in the polymer density difference?30) Which of the below given characterization technique can be used to identify the surfacechemistry of a biomaterial?а) ТЕМb) XPSc) TGAd) DTA31) Sort the wettability for the given surfaces based on the given contact angle values ( non-wetting, good wetting, incomplete wetting ?a =90a <90a >180

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29) Polyethylene can be obtained in two different forms. High-density polyethylene (0.94 g/cm3 is a linear polymer. Low-density polyethylene (0.92 g/cm3) is a branched polymer with short side-chains on 3% of the atoms along the polymer chain. What could be the reason of the change in the polymer density difference?

29) Polyethylene can be obtained in two different forms. High-density polyethylene (0.94 g/cm3 is a linear polymer. Low-density polyethylene (0.92 g/cm3) is a branched polymer with short side-chains on 3% of the atoms along the polymer chain. What could be the reason of the change in the polymer density difference?

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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2. | Calculate the overall charge (pH 7) on the following three polypeptides and answer the questions below. Assume the following pKa values: N-terminal -NH3®, 7.0; all -COOH groups, 4.0; Arg, 12.5; Cys, 8.4; His, 6.0; Lys, 10.0; Tyr, 10.0. (A) Ser-Tyr-Ser-Met-Glu-His-Phe-Arg-Trp-Gly-Lys-Pro-Val-Gly-Lys-Lys-Arg-Arg-Pro-Val-Lys-Val-Tyr-Pro-Asp-Ala -Gly- Glu-Asp-Gln- Ser-Ala-Glu-Ala-Phe-Pro-Leu-Arg-Glu-Phe (B) Ser-Tyr-Ser-Met-Glu–His-Phe-Arg–Trp–Gly-Ala-Pro-Val-Gly-Glu-Glu-Cys-Asp-Pro-Val-Glu–Val-Tyr-Pro-Asp- Ala-Gly-Glu-Asp-Gln-Ser-Ala-Glu-Ala-Phe-Pro-Leu-Glu-Phe-Cys-Ser-Tyr-Ser-Met-Glu-His-Phe-Asp-Trp-Gly- Asp-Pro-Val-Gly-Pro-Asp-Ala-Gly-Asp-Gln-Pro-Val-Gly-Glu-Glu-Cys-Asp-Pro-Val-Glu-Val-Tyr-Pro-Asp-Ala | (C) Gly-Ser-Val-Arg-Asp-Pro-Val-Lys-Glu–Val-Tyr-Pro-Asp- Lys-Ala-Gly-Arg-Glu-Ser-Arg-Ala (a) Which of the three peptides would elute first from a gel filtration column? (b) Which of the three peptides would migrate the fastest on SDS-PAGE (c) Which of the three peptides could be…
3. How will you prepare 500 ml of 0.750 M citrate buffer with pH of 4.25 from solid citric acid (C6H8O7) and solid sodium citrate (Na3C6H5O7). The Ka of citric acid is 7.40 x 10-4 . Given: • (Na3C6H5O7) solid sodium citrate = conjugate base in molarity [? −] • (C6H8O7) solid citric acid = weak acid in molarity [??] • 7.40 × 10−4 ?? of citric acid = ??? (acid-dissociation constant) • 500 ml of 0.750 M citrate buffer
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