Below is the titration of histidine. Calculate the average charge of histidine at pH 6.50. ÇOON Histidine 10 pK, - 9.17 pl= 7.59 6.0 PH pK, = 1.82 1.0 2.0 3.0 OH" (equivalents)
Below is the titration of histidine. Calculate the average charge of histidine at pH 6.50. ÇOON Histidine 10 pK, - 9.17 pl= 7.59 6.0 PH pK, = 1.82 1.0 2.0 3.0 OH" (equivalents)
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:6. Below is the titration of histidine. Calculate the average charge of histidine at pH 6.50.
соон
Ç00
çoo
HN-CH
HN-CH
HN-CH
CH, H
CH, H
CH, H
CH, H
CH
CH
pK.
CH
pk.
pK.
HN
+2
+1
pK, =
Histidine
10
9.17
8
pK =
6.0
pl =
7.59
6
PH
pk, =
1.82
2..
1.0
2.0
3.0
OH (equivalents)
7. Consider the following reaction
Malate + NAD+ → oxaloacetate + NADH + H* AG" = 29.7 kJ/mol
a. The concentration of NAD+ and NADH are 20 mM and 0.3 mM, respectively. If malate is 0.4 mM, what is the maximum concentration of oxaloacetate needed to make the reaction exergonic at pH 7.0 and 37 °C?
b. Which species is oxidized the malate of the oxaloacetate?
c. Calculate AGO' using the reduction potentials look in your text for the values. How does it compare to AG" = 29.7 kJ/mol?
AG" = -nFAE°r = -nF|E (r accepier)
- E°
(e donor)
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