PROMLEM # 22.a.Find the heat coupau tg of hot and cold fland.massat a pressure = 2at m and flow rate = Il020 kg /min.the temp erature of hot water is being decreased from248.09°F to 212.09 oF u= 1020 kg /min,singa heat exchanger.Reservvir wateru used asw coolant withmass flow rate = 1800 ka Imin andinlet temperatureThe ft?50.09 of.ニ2.minimum allow ableof heat ex changersurface are a = 270.17all ow able overall heat = 204.05 btu/Thetransfer coefficient of heat exchangerThe heat capaci tythe average vame ofmaxi mum%3Ddo z7f Yinlet and out let temperatures.y to be ustd must be

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# 22.9. Find the heat coupou ty of hot and cold fluid. mass a pressure = 2at m and flow rate = 1020 kg/Imin, mperature of hot water is being decreased from 09 OF to 212.09 OF using a heat exchanger. ir waten u used as coolant with low rate = 1800 ka lmin and Femperature = minimum allow able surface are a = 270. 17 of heat 50.09 of. ex changer all ow able overall heat = 204.05 btu / %3D maxi muum sfer coefficient of heat exchanger USY di must be

# 22.9. Find the heat coupou ty of hot and cold fluid. mass a pressure = 2at m and flow rate = 1020 kg/Imin, mperature of hot water is being decreased from 09 OF to 212.09 OF using a heat exchanger. ir waten u used as coolant with low rate = 1800 ka lmin and Femperature = minimum allow able surface are a = 270. 17 of heat 50.09 of. ex changer all ow able overall heat = 204.05 btu / %3D maxi muum sfer coefficient of heat exchanger USY di must be

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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