PROBLEM # 22.a.mass1020 kg /min,the temperature of hot water is being decreased fromto 212.09 oF using a heat exchanger.at aa pressure = 2at m and flow rate=248.09°FReservoir watenu used as Wcoolant withmass flow rate = 1800 kalmin andinlet temperature = 50.09 of.The minimun allow able surface are a = 270. 17 fto4 heat ex changer2.%3Dall ow able overall heat = 204.05 btu/Thetransfer coefficient of heat exchangermaxi mum%3D2The heat to be use d must becapaci tyof inet and outlet temperaturesthe average valueFind the Number of Transfer units (NTU) usingeffective nessesch angerwsingNTU metho d if the heatbeing used isheat exchangerparallel -flow double-pipe

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-2.a. mass = 2at m and flow rate = 1020 kg /min, rature of hot water is being decreased from a heat exchanger. ご PF to 212.09 °F using water u used as w coolant with rate = 1800 kg Imin and erauture = 50.09 of. = 270. 17 ft? mum allow able surface are a of heat ex changer all ow able overall heat = 206.05 btu/ -xi muem colfficient of heat exchanger 2. paci ty to be use d must be age value of inMet and outlet temperaturees.

-2.a. mass = 2at m and flow rate = 1020 kg /min, rature of hot water is being decreased from a heat exchanger. ご PF to 212.09 °F using water u used as w coolant with rate = 1800 kg Imin and erauture = 50.09 of. = 270. 17 ft? mum allow able surface are a of heat ex changer all ow able overall heat = 206.05 btu/ -xi muem colfficient of heat exchanger 2. paci ty to be use d must be age value of inMet and outlet temperaturees.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter10: Heat Exchangers

Section: Chapter Questions

Problem 10.25P

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