kinetic values should be more than 10% different 2. The kinetics of an enzyme are measured as a function of substrate concentration in the presence andabsence of 100 uM inhibitor. Show calculations, include the table of values needed to make your graphsand provide full explanations for each of the following.Velocity (uM/minute)[S] (UM)No inhibitorInhibitor310.42.1514.52.91022.54.53033.86.89040.58.1i) Calculate the values of Km and Vmax in the absence of the inhibitor? Show all calculations. Circle yourfinal answers. Make sure units are included.{insert calculations here}ii) What are the values of Km and Vmax in the presence of the inhibitor? Show all calculations. Circleyour final answers. Make sure units are included.{insert calculations here}iii) What type of inhibition is this? Explain your reasoning{insert answer and explanation here}

Enzymes are catalysts that increase the rate of biochemical reactions. The inhibition of enzyme…

2. The kinetics of an enzyme are measured as a function of substrate concentration in the presence and absence of 100 uM inhibitor. Show calculations, include the table of values needed to make your graphs and provide full explanations for each of the following. Velocity (uM/minute) [S] (UM) No inhibitor Inhibitor 3 10.4 21 5 14.5 2.9 10 22.5 4.5 30 33.8 6.8 90 40.5 8.1

2. The kinetics of an enzyme are measured as a function of substrate concentration in the presence and absence of 100 uM inhibitor. Show calculations, include the table of values needed to make your graphs and provide full explanations for each of the following. Velocity (uM/minute) [S] (UM) No inhibitor Inhibitor 3 10.4 21 5 14.5 2.9 10 22.5 4.5 30 33.8 6.8 90 40.5 8.1

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Subject: chemistry
Biomedical Engineering- Bridging Medicine and Technology -- W. Mark Saltzman 2009 In Section 9.2, the text discusses the zero-order kinetics of alcohol disappearance from the blood. a. Using the approach outlined in section 7.2.2 (Tracer balance in the body), find an equation describing the concentration of alcohol in the plasma versus time, given that the initial concentration in the plasma (at time=0) is 10 mM.(Refer to Figure 9.5, the half-life of alcohol in plasma is 150 min) b. Graph the results of (a). c. Over what time interval is the expression that you derived in (a) valid? Why is it not valid for all time?
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29 (RBE) value of 20 for the a radiation, calculate the equivalent dose In miner in that year Problem 7: A patient with with uveal melanoma is treated at a cyclotron facility with energetic protons directed at a tumor in their eye, with a dose of 1.0 Gy administered over five sessions, What is the equivalent dose in Sv to the tumor? A 6 Type of Radiation O Sv X-rays 7-rays / rays > 32 kev rays <32 ke V Neutrons, thermal to slow (< 20 keV) Neutrons, fast (1 – 10 MeV) Protons (1 - 10 MeV) a-rays from radioactive decay to the lungs of the 17 10 (body), 32 (eyes) 10 (body), 32 (cycs) 20
Major functional groups present and expected wavenumbers of the peaks: Attach IR spectrum of the compound and list wavenumbers of signals/peaks observed in the spectrum: Discussion
Please explain your reasoning for every answer
NaOH.2L X.02mol/L = .004 mol, H3PO4.8L X.15 mol/L = .12 mol H₂PO4 HPO4² + H+ .108 mol start A. If 200 mls of 0.02 M NaoH is added to 800 mls of 0.15 M phosphoric acid buffer at pH 8.2, what is the resultant pH? (pK1 = 2.1, Pk2=7.2, pk3=12.2) add .004 mol OH- end .012mol -.004 .008 mol pH= pka + log [A-]/[HA] = 7.2 + log.112/.008 +.004 .112mol pH=8.35 B. If the same amount of NaOH in part A is added to 800 mls of water, what is the resulting pH? .004mol/1L =.004 [OH-] pOH = 2.4, pH -11.6
Time (min) 0 15 30 45 60 75 Solution A Weight (8) 4.205 4.032 3.787 3.648 3.550 3.500 Change (%) Solution B Weight (8) 3.611 -4.11% 3.606 -6.07% 3.622 -3.67% 3.662 -2.69% 3.706 1.41% 3.732 Change (%) Solution с Weight (8) 4.257 -0.138% 4.213 0.444% 4.219 4.209 Change (%) 4.210 -1.03% Solution D Weight (8) 4.728 4.513 0.142% 4.350 1.10% 0.237% 4.254 1.20% 0.024% 4.068 0.675% 4.209 -0.024% 4.140 Change (%) -4.55% -3.61% -2.21% -4.37% 1.77% Graph your results below, plotting percent weight change versus time for all 4 unknown solutions on one set of axes, labeled clearly with units. Include a title for your graph.