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A. If 200 mls of 0.02 M NaoH is added to 800 mls of 0.15 M phosphoric acid buffer at pH 8.2, what is the resultant pH? (pK1 = 2.1, Pk2=7.2, pK3=12.2) NaOH.2LX.02mol/L = .004 mol, H3PO4.8LX.15 mol/L = .12 mol HPO4² + H+ H₂PO4 .012mol .108 mol start add.004 mol OH- -.004 end pH= pka + log [A-]/[HA] = 7.2 + log.112/.008 .008 mol +.004 .112mol pH=8.35 B. If the same amount of NaOH in part A is added to 800 mls of water, what is the resulting pH?

A. If 200 mls of 0.02 M NaoH is added to 800 mls of 0.15 M phosphoric acid buffer at pH 8.2, what is the resultant pH? (pK1 = 2.1, Pk2=7.2, pK3=12.2) NaOH.2LX.02mol/L = .004 mol, H3PO4.8LX.15 mol/L = .12 mol HPO4² + H+ H₂PO4 .012mol .108 mol start add.004 mol OH- -.004 end pH= pka + log [A-]/[HA] = 7.2 + log.112/.008 .008 mol +.004 .112mol pH=8.35 B. If the same amount of NaOH in part A is added to 800 mls of water, what is the resulting pH?

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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NaOH.2L X.02mol/L = .004 mol, H3PO4.8L X.15 mol/L = .12 mol H₂PO4 HPO4² + H+ .108 mol start A. If 200 mls of 0.02 M NaoH is added to 800 mls of 0.15 M phosphoric acid buffer at pH 8.2, what is the resultant pH? (pK1 = 2.1, Pk2=7.2, pk3=12.2) add .004 mol OH- end .012mol -.004 .008 mol pH= pka + log [A-]/[HA] = 7.2 + log.112/.008 +.004 .112mol pH=8.35 B. If the same amount of NaOH in part A is added to 800 mls of water, what is the resulting pH? .004mol/1L =.004 [OH-] pOH = 2.4, pH -11.6
Transcribed Image Text:NaOH.2L X.02mol/L = .004 mol, H3PO4.8L X.15 mol/L = .12 mol H₂PO4 HPO4² + H+ .108 mol start A. If 200 mls of 0.02 M NaoH is added to 800 mls of 0.15 M phosphoric acid buffer at pH 8.2, what is the resultant pH? (pK1 = 2.1, Pk2=7.2, pk3=12.2) add .004 mol OH- end .012mol -.004 .008 mol pH= pka + log [A-]/[HA] = 7.2 + log.112/.008 +.004 .112mol pH=8.35 B. If the same amount of NaOH in part A is added to 800 mls of water, what is the resulting pH? .004mol/1L =.004 [OH-] pOH = 2.4, pH -11.6
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