2) SIM D *8.29 The differential amplifier in Fig. P8.29 uti- lizes a resistor R to establish a 1-mA dc bias current. Note that this amplifier uses a single 5-V supply and thus the dc common-mode voltage VCM cannot be zero. Transistors Q and Q₂ have KW/L=2.5 mA/V², V₁=0.7 V, and λ = 0. (a) Find the required value of VCM- (b) Find the value of R, that results in a differential gain A, of 8 V/V. (c) Determine the dc voltage at the drains. (d) Determine the common-mode gain AVD/AVCM. (Hint: You need to take 1/g into account.) (e) Use the common-mode gain found in (d) to determine the change in VCM that results in Q, and Q₂ entering the tri- ode region. Vid VCM Figure P8.29 RD VDD=5 V 2₁ Vod + RD 1 mARss=1kn

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2)
SIM D *8.29 The differential amplifier in Fig. P8.29 uti-
lizes a resistor Rs to establish a 1-mA dc bias current. Note
that this amplifier uses a single 5-V supply and thus the dc
common-mode voltage VCM cannot be zero. Transistors Q
and Q₂ have KW/L = 2.5 mA/V², V₁= 0.7 V, and λ = 0.
(a) Find the required value of VCM-
(b) Find the value of R, that results in a differential gain A
of 8 V/V.
(c) Determine the de voltage at the drains.
(d) Determine the common-mode gain AVD/AVCM. (Hint:
You need to take 1/gm into account.)
(e) Use the common-mode gain found in (d) to determine
the change in VCM that results in Q, and Q₂ entering the tri-
ode region.
Vid
VCM
Figure P8.29
RD
2₁
-Vss
VDD=5 V
O od 0
1 mA
2₂
RD
Rss = 1 kn
Transcribed Image Text:2) SIM D *8.29 The differential amplifier in Fig. P8.29 uti- lizes a resistor Rs to establish a 1-mA dc bias current. Note that this amplifier uses a single 5-V supply and thus the dc common-mode voltage VCM cannot be zero. Transistors Q and Q₂ have KW/L = 2.5 mA/V², V₁= 0.7 V, and λ = 0. (a) Find the required value of VCM- (b) Find the value of R, that results in a differential gain A of 8 V/V. (c) Determine the de voltage at the drains. (d) Determine the common-mode gain AVD/AVCM. (Hint: You need to take 1/gm into account.) (e) Use the common-mode gain found in (d) to determine the change in VCM that results in Q, and Q₂ entering the tri- ode region. Vid VCM Figure P8.29 RD 2₁ -Vss VDD=5 V O od 0 1 mA 2₂ RD Rss = 1 kn
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