This problem is AC analysis problem. DC analysis is not needed to answer the question. 9) A. If lp = 1.1 mA, VG = 3.43V, Vs = 1.1V, and Vp = 8.71 V in the Common Source Amplifier below calculate the gain (Vo/Vi) of the circuit. Vo is taken across the Load resistor. Answer: Vo/Vi =. B. For the circuit in problem 9 what would be the ideal DC voltage of the drain so you could achieve Maximum Signal Swing. Given: Ve = 3.43 V. Answer: Vo =. > When you "verify" a mode of operation you will need to calculate all three voltages (Vc, V8, Ve for BJTS and VG, Vs, Vp for MOSFETS) and show the correct two conditions are satisfied. > Assume Capacitors acts like open circuits at DC and short circuits for AC. > Assume the following: o Beta = 100 o VBE = 0.7 o V: (Thermal) = 26 mV o V (Threshold) = 2V O VA = - o For MOSFET saturation mode: assume: lo = K(Vas-Vr)? 12V R2 3kn R1 10k C2 (Assume K = 10 mA/V?). R Load >10kn 1µF C1 R_sig 1kn 1pF R4 4kn R3 1kn C3 Vi

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.