19 A balanced three-phase voltage source, Van = 200/0° V rms, positive phasesequence, is connected to an unbalanced A load: ZAB= 60 + 10, Zgc = 30 + 130,ZCA 30-130 2. Find: (a) the three phasor line currents; (b) the power de-livered to each phase of the load; (c) the power provided by each phase of thesource.

Answered: Image /qna-images/answer/1d05a689-c1cd-477e-8b10-56716d71edd4.jpg

19 A balanced three-phase voltage source, Van = 200/0° V rms, positive phase sequence, is connected to an unbalanced A load: ZAB= 60 + 10, ZBC = 30 + 130, ZCA 30-130 2. Find: (a) the three phasor line currents; (b) the power de- livered to each phase of the load; (c) the power provided by each phase of the source.

19 A balanced three-phase voltage source, Van = 200/0° V rms, positive phase sequence, is connected to an unbalanced A load: ZAB= 60 + 10, ZBC = 30 + 130, ZCA 30-130 2. Find: (a) the three phasor line currents; (b) the power de- livered to each phase of the load; (c) the power provided by each phase of the source.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Need help with part b
If a A-connected load has a balanced impedance ZA 94 - 17° 2 and a voltage = = / VBC = 265 82° V rms, what is the magnitude of the current Ia (in A rms)? C V cn Van a Answer: n Von b Ia Ib 20 B IAB IBC ZA ZA ICA C
Three Impedances each of (9 - j18)N are connected in mesh across a three-phase 415V ac supply. Determine the phase current, line current, active power, reactive power drawn from supply. Also draw the Phasor diagram for the mesh connection and marks the Line current ,phase current line voltage and phase angle between phase current and pahse voltage. phase current (Ip) Line current real power reactive power
5 and 6
Sum of scattering angles in Laboratory coordinate system is always equal to * O 2n None of them О п/2
A three-phase alternator generating unbalanced voltages is connected to an unbalanced load through a 3-phase transmission line as shown in figure. The neutral of the alternator and the star point of the load are solidly grounded. The phase voltages of the alternator are Ea = 1020º, Eb = 102-90°, Ec = 10/120⁰ E E E The positive sequence component of the load current is (A) 1.3102-107⁰ A (B) 0.3322-120° A (C) 0.9962-120º A (D) 3.5104-81⁰ A +) + j1.002 0000 j1.002 0000 j1.0Ω vovo j1.0Ω 0000 j2.002 voor j3.002 oooo
Answer Number 6 Write your Solution Pls Box your Final answer.
Determine the value of the impedance, Z₁, that causes maximum power transfer in the circuit shown in Figure Qlc. 52 j24n -j12.35n (V₂) j2403 j24n Figure Qle B
A 25 kVA, 240 V single phase source supply the rated power at the rated voltage to a motor at 0.8 power factor lagging. Find the capacitor bank in order to improve the power factor to 0.9 lagging. connected to a motor. a. Calculate the real power, reactive power and current before capacitor bank is connected? P= Q= b. Calculate the power and reactive power after capacitor bank is connected? P = c. What is kVA rating of capacitor bank Qc?
Impedances Z1 = 5.83 at angle of -59 deg. and Z2 = 8.94 at an angle of 63.43 deg. are in series and carry an effective current of 5A. Determine the Power and power factor of the circuit indicating if it is leading or lagging.
Q4 a) A three-phase system has a rms phase voltage of 6.3 kV. What is the line voltage?
A balanced load is connected in star across a 3 phasec415V 50Hz supply. The load consists of a coil of resistance 25 ohms and inducrance 0.5 henry in paeallel with a purw resistance of 28 ohms and a pure capaciror of 60microfarads capacitance ,in each branch. Calculate a. The line currents? Need full working and answer has to be 9.3A Formola for inductance XL= 2×3.142FL FORMOLA FOR CAPACITOR XC= 1/2×3.142×FC