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Q.22: For the magnetically coupled circuit shown, find the voltage across (-J10Q) 10:00V 52 JS2 JSS 552 10:900V impedance and the total power? J102 (Ans.: Vc=10.15Z23.96°V & Pr=17.3W)

Q.22: For the magnetically coupled circuit shown, find the voltage across (-J10Q) 10:00V 52 JS2 JSS 552 10:900V impedance and the total power? J102 (Ans.: Vc=10.15Z23.96°V & Pr=17.3W)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Q.22: For the magnetically coupled circuit shown, find the voltage across (-J10Q) 10:00V impedance and the total power? Vc=10.15Z23.96°V JS2 JSS 52 10:900V J102 (Ans.: Pr=17.3W) &
Transcribed Image Text:Q.22: For the magnetically coupled circuit shown, find the voltage across (-J10Q) 10:00V impedance and the total power? Vc=10.15Z23.96°V JS2 JSS 52 10:900V J102 (Ans.: Pr=17.3W) &
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