14. Calculate v, and the degree of inhibition caused by a competitive inhibitor under the following conditions: (a) [S] = 2 x 10-3 M and [I] = 2 x 103 M (b) [S] = 4 x 104 M and [I] = 2 x 10-3 M (c) [S] = 7.5 x 10-3 M and [I]= 10-$ M Assume that Km = 2 x 10-3 M, K; = 1.5 x 104 M and Vmax = 270 nmoles x liter x min-. The degree of inhibition is the percent of the uninhibited velocity reached in the presence of the inhibitor. %3D
14. Calculate v, and the degree of inhibition caused by a competitive inhibitor under the following conditions: (a) [S] = 2 x 10-3 M and [I] = 2 x 103 M (b) [S] = 4 x 104 M and [I] = 2 x 10-3 M (c) [S] = 7.5 x 10-3 M and [I]= 10-$ M Assume that Km = 2 x 10-3 M, K; = 1.5 x 104 M and Vmax = 270 nmoles x liter x min-. The degree of inhibition is the percent of the uninhibited velocity reached in the presence of the inhibitor. %3D
Biochemistry
9th Edition
ISBN:9781305961135
Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Chapter15: The Importance Of Energy Changes And Electron Transfer In Metabolism
Section: Chapter Questions
Problem 15RE: MATHEMATICAL If a reaction can be written AB, and the G is 20kJmol1, what would the...
Related questions
Question
The problem set question is below. In the image
![**Problems 14 and 15: Some of the exponents are unclear. Here they are:**
14. Calculate \( v_i \) and the degree of inhibition caused by a competitive inhibitor under the following conditions:
(a) \([S] = 2 \times 10^{-3} \, \text{M and} \, [I] = 2 \times 10^{-3} \, \text{M}\)
(b) \([S] = 4 \times 10^{-4} \, \text{M and} \, [I] = 2 \times 10^{-3} \, \text{M}\)
(c) \([S] = 7.5 \times 10^{-3} \, \text{M and} \, [I] = 10^{-5} \, \text{M}\)
Assume that \( K_m = 2 \times 10^{-3} \, \text{M}, \, K_i = 1.5 \times 10^{-4} \, \text{M} \) and \( V_{max} = 270 \, \text{nmoles} \times \text{liter}^{-1} \times \text{min}^{-1} \).
The degree of inhibition is the percent of the uninhibited velocity reached in the presence of the inhibitor.
15. (a) What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of \( 1.5 \times 10^{-3} \, \text{M} \) if \( K_m = 2.9 \times 10^{-4} \, \text{M} \) and \( K_i = 2 \times 10^{-5} \, \text{M} \)?
(b) To what concentration must the substrate be increased to reestablish the velocity at the original uninhibited value?
**Note:** The questions are designed to test understanding of enzyme kinetics, focusing on competitive inhibition, the Michaelis-Menten equation, and the concept of \( K_i \), the inhibition constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe77e44c7-8f97-4332-8d23-eb24d773472e%2F8b817005-3f1e-458e-b06f-ec6e3f986fb7%2F5q0yny7b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problems 14 and 15: Some of the exponents are unclear. Here they are:**
14. Calculate \( v_i \) and the degree of inhibition caused by a competitive inhibitor under the following conditions:
(a) \([S] = 2 \times 10^{-3} \, \text{M and} \, [I] = 2 \times 10^{-3} \, \text{M}\)
(b) \([S] = 4 \times 10^{-4} \, \text{M and} \, [I] = 2 \times 10^{-3} \, \text{M}\)
(c) \([S] = 7.5 \times 10^{-3} \, \text{M and} \, [I] = 10^{-5} \, \text{M}\)
Assume that \( K_m = 2 \times 10^{-3} \, \text{M}, \, K_i = 1.5 \times 10^{-4} \, \text{M} \) and \( V_{max} = 270 \, \text{nmoles} \times \text{liter}^{-1} \times \text{min}^{-1} \).
The degree of inhibition is the percent of the uninhibited velocity reached in the presence of the inhibitor.
15. (a) What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of \( 1.5 \times 10^{-3} \, \text{M} \) if \( K_m = 2.9 \times 10^{-4} \, \text{M} \) and \( K_i = 2 \times 10^{-5} \, \text{M} \)?
(b) To what concentration must the substrate be increased to reestablish the velocity at the original uninhibited value?
**Note:** The questions are designed to test understanding of enzyme kinetics, focusing on competitive inhibition, the Michaelis-Menten equation, and the concept of \( K_i \), the inhibition constant.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Biochemistry
Biochemistry
ISBN:
9781305961135
Author:
Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:
Cengage Learning
Biochemistry
Biochemistry
ISBN:
9781305577206
Author:
Reginald H. Garrett, Charles M. Grisham
Publisher:
Cengage Learning
Biochemistry
Biochemistry
ISBN:
9781305961135
Author:
Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:
Cengage Learning
Biochemistry
Biochemistry
ISBN:
9781305577206
Author:
Reginald H. Garrett, Charles M. Grisham
Publisher:
Cengage Learning
Case Studies In Health Information Management
Biology
ISBN:
9781337676908
Author:
SCHNERING
Publisher:
Cengage