14-95 Air at 1 atm, 20°C, and 50 percent relative humidity is first heated to 35°C in a heating section and then passed through an evaporative cooler where its temperature drops to 25°C. Determine (a) the exit relative humidity and (b) the amount of water added to air, in kg H₂O/kg dry air.
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- T = -25°C A 0.5 m × 1 m double paned window is made of two silica glass panes 1 cm thick, with air in between. Under steady conditions, linear (constant gradient) Outdoors temperature profiles are found in both silica panes, as well as the air. If the room (and the inner surface of h=18Wm²K the inner glass pane) is at a temperature of 25°C, while outdoors it is -25°C with a convection coefficient of 18 W m² K-1, what is the rate of heat loss through the window? What is the rate of heat loss if the room temperature is decreased to 20°C? Finally, what is the rate of heat loss for a room temperature of 25°C, but with one of the panes (and the air) removed? 1 cm 1 cm Room Temperature, 25° C or 20º C 0.5 mm Air, k=0.024 W m¹ K¹ Silica glass, k = 0.90 W m³ KA. Choudhury’s bowling ball factory in Illinois makes bowling balls of adult size and weight only. The standard devia-tion in the weight of a bowling ball produced at the factory is known to be 0.12 pounds. Each day for 24 days, the averageweight, in pounds, of nine of the bowling balls produced that dayhas been assessed as follows: a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control lim-its are each two standard deviations from the mean. What are the values of the control limits?b) If three standard deviations are used in the chart, how do thesevalues change? Why?7
- 2) The specification for a Lindemann’s stainless steel chimney liner requires a thickness of 7.1 mm ± 0.1 mm. The firm’s quality analyst determines that the liner process operates at a mean thickness of 7.13 mm with the standard deviation of the process being 0.02 mm. a) Calculate the upper and the lower limits for the stainless steel chimney liner. b) Calculate the Cpand Cpkfor this process. Hint: Cp = (Upper Specification Limit – Lower Specification Limit)/6sigma Cpk = minimum of [(Upper Specification Limit – Xbar)/3sigma], [(Xbar – Lower Specification Limit)/3sigma]The specifications for a gasket that installs between two engine parts calls for a thickness of 6.0 mm ± .2 mm. The standard deviation of the process is estimated to be 0.05 mm. The process is known to operate at a mean thickness of 6.1 mm What are the upper and lower specification limits for the gasket? What are the Cp and Cpk values for this process? Is this process capable of producing the desired part?Webster Chemical’s nominal weight for filling tubes of caulk is 8.00 ounces ± 0.60 ounces. The target process capability ratio is 1.33. The current distribution of the filling process is centered on 8.054 ounces with a standard deviation of 0.192 ounces. Compute the process capability ratios Cp and Cpk to assess whether the filling process is capable and set properly.
- Suppose that material hardness is normally distributed with a mean of 52 and a standard deviation of 1. Specification limits for hardness are from 45 to 55. What is Cp?Bill Kime's bowling ball factory makes bowling balls of adult size and weight only. The standard deviation in the weight of a bowling ball produced at the factory is known to be 0.39 pounds. Each day for 24 days, the average weight, in pounds, of 9 of the bowling balls produced that day has been assessed as follows Day 1 2 3 4 5 6 Average (lb) 9.9 9.9 10.1 10.1 99 99 Day 7 8 9 10 11 12 Average (lb) Day Average (b) 13 14 15 16 17 18 10.1 10.0 10.0 10.1 10.1 10.0 9.9 10.1 10.1 10.0 10.1 10.1 Day 19 20 21 22 23 24 Average (lb) 99 10.0 10.1 9.9 10.0 10.0 a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean What are the values of the control limits? Upper Control Limit (UCL)=b (Round your response to two decimal places)Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to 726 ° C a)Is the steel hypereutectoid or hypoeutectoid b)What is the primary microconstituent (proeutectoid)phase? c)How many kilograms of total ferrite and cementite form? d)How many kilograms each of pearlite and the proeutectoid phase form? Weight percent carbon
- Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 5 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean (mm) Range R (mm) 158 4.3 151.2 4.4 155.7 4.2 153.5 4.8 156.6 4.5 What is the UCL using 3-sigma?(round your response to two decimal places). 1. 2. 4.A machine is used to fill cans of motor oil additive. A single sample can is selected every hour and the net weight of the can is obtained. Since the filling process is automated, it has very stable variability, and long experience indicates that s = 0.02 oz. The process target (process mean when in control) is 8.02 oz. A tabular cusum is being used for this process with standardized values h=4.5 and k=0.5. If the values of Cumulative sums at the end of measurement 7 were C," + = 0.030 and C,¯ = 0.0 , and measurement 8 is equal to Xg = 8.071, what will be the Cumulative sum at the end of measurement 8, that is C3 + = ? 0.041 0.071 0.051 0.046 0.061The temperature of a burrito served to a customer in a local Mexican restaurant A: Discrete B; Continous