13 Match each of the QPCR samples (i-v) with the correct amplification plot (A-E) and determine the Ct value for each of the amplification curves. Number of template copies in the QPCR reaction: Amplification plot (A-E): Ct Value 1200 1000 i. 1X 106 ii. 1X 105 iii. 1X 108 iv. 1X 107 V. NTC (No template control) 800 600 400 200 A C 0 5 10 15 20 25 30 Cycles vi. Create a standard curve graph of template copies vs Ct with the data in the table above. Log of Starting Quantity of DNA vrs C+ vii. 26 24 22221 20 18 16 14 12 כי 10 8 6 4 2 0 5 5.5 6 6.5 7 7.5 8 Log Starting Quantity of DNA (Template copies) If a patient sample has a Ct of 20, interpolate the number of template copies at the start of the PCR reaction using the standard curve you created above?

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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13 Match each of the QPCR samples (i-v) with the correct amplification plot (A-E) and
determine the Ct value for each of the amplification curves.
Number of template copies
in the QPCR reaction:
Amplification
plot (A-E):
Ct Value
1200
1000
i.
1X 106
ii. 1X 105
iii. 1X 108
iv. 1X 107
V.
NTC (No template control)
800
600
400
200
A
C
0
5
10
15
20
25
30
Cycles
vi. Create a standard curve graph of template copies vs Ct with the data in the table above.
Log of Starting Quantity of DNA vrs C+
vii.
26
24
22221
20
18
16
14
12
כי
10
8
6
4
2
0
5
5.5
6
6.5
7
7.5
8
Log Starting Quantity of DNA (Template copies)
If a patient sample has a Ct of 20, interpolate the number of template copies at the start of the PCR
reaction using the standard curve you created above?
Transcribed Image Text:13 Match each of the QPCR samples (i-v) with the correct amplification plot (A-E) and determine the Ct value for each of the amplification curves. Number of template copies in the QPCR reaction: Amplification plot (A-E): Ct Value 1200 1000 i. 1X 106 ii. 1X 105 iii. 1X 108 iv. 1X 107 V. NTC (No template control) 800 600 400 200 A C 0 5 10 15 20 25 30 Cycles vi. Create a standard curve graph of template copies vs Ct with the data in the table above. Log of Starting Quantity of DNA vrs C+ vii. 26 24 22221 20 18 16 14 12 כי 10 8 6 4 2 0 5 5.5 6 6.5 7 7.5 8 Log Starting Quantity of DNA (Template copies) If a patient sample has a Ct of 20, interpolate the number of template copies at the start of the PCR reaction using the standard curve you created above?
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