11: ASquare foundation is required to Carry a totalload of 660 KN in cohesionless soil. The water tablelocates at the base of foundation. Determine the widthof the foundation? (Use Terzaghi equation).Note:Jd=18 kN/m²3Depth of foundation = 1.2 mFactor of Safety = 30° = 25४.8 satర3= 20 KN/m³3Ow = 10 kN/m²Assume the allowable bearing Capacity is equal tothe actual bearing Capacity (I actual).

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Answered: 11: A Square foundation is required to…

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter4: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 4.6P

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A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, =15.9 kN/m3, = 34, and c = 0. Use Terzaghis equation to determine the size of the foundation (B). Assume general shear failure.
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]
A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: = 19.5 kN/m3, c = 0 and =34. Determine the maximum wall load that the foundation can carry, with a factor of safety of 3.0, using a. Terzaghis original bearing capacity equation with his bearing capacity factors b. Meyerhofs modified bearing capacity equation with appropriate factors (Tables 16.2 and 16.3).
A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: Df = 1.5 m, ф′ = 25°, c′ = 70 kN/m2. Using Eq. (6.28) and FS = 3, determine the net allowable load [see Eq. (6.24)] the foundation could carry. Figure P6.9
A column foundation (Figure 16.23) is 3 m 2 m in plan. Given: Df = 1.5 m, =25, c = 70 kN/m2. Using Eq. (16.9) and FS = 3, determine the net allowable load [see Eq. (16.16)] the foundation could carry. FIG. 16.23
It is proposed to place a 9 ft 9 ft foundation at 6 ft depth in a sandy soil, where the average N60 is 25 and the unit weight is 115.0 lb/ft3. Using Meyerhofs expressions presented in Section 9.6, estimate the allowable net pressure that would give 1.2 in. of settlement.
A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).
Repeat Problem 16.13 with the following: Mat foundation: B = 8 m, L = 20 m, and Df = 2 m Clay: =0 and cu = 130 kN/m2 16.13 A mat foundation measuring 14 m 9 m has to be constructed on a saturated clay. For the clay, cu = 93 kN/m2 and =0. The depth, Df, for the mat foundation is 2 m. Determine the net ultimate bearing capacity.
A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: γ = 19.5 kN/m3, c′ = 0, and ф′ = 34°. Determine the maximum wall load that the foundation can carry, with a factor of safety of 3.0, using Terzaghi’s original bearing capacity equation with his bearing capacity factors, and Meyerhof’s general bearing capacity equation with shape, depth, and inclination factors from Table 6.3.
For the following cases, determine the allowable gross vertical load-bearing capacity of the foundation. Use Terzaghi’s equation and assume general shear failure in soil. Use FS = 4. Parameters for Problem 6.1
A continuous foundation is required in a soil where c=10kN/m2, =26, and =19.0kN/m3. The depth of the footing will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (6.10) and Table 6.1.
The applied load on a shallow square foundation makes an angle of 20° with the vertical. Given: B = 5 ft, Df = 3 ft, γ = 115 lb/ft3, ф′ = 25°, and c′ = 600 lb/ft2. Use FS = 3 and determine the gross inclined allowable load. Use Eq. (6.28).

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