11: ASquare foundation is required to Carry a totalload of 660 KN in cohesionless soil. The water tablelocates at the base of foundation. Determine the widthof the foundation? (Use Terzaghi equation).Note:Jd=18 kN/m²3Depth of foundation = 1.2 mFactor of Safety = 30° = 25४.8 satర3= 20 KN/m³3Ow = 10 kN/m²Assume the allowable bearing Capacity is equal tothe actual bearing Capacity (I actual).

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Answered: 11: A Square foundation is required to…

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter4: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 4.6P

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A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, =15.9 kN/m3, = 34, and c = 0. Use Terzaghis equation to determine the size of the foundation (B). Assume general shear failure.
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A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, p' = 30°, c' = 80 kN/m². Using the general bearing capacity equation (CFEM - see class slides from March 17 - similar to Example 1 and 2 but with an added capacity term related to cohesion) and = 0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, N₁, and Ny directly from the table on page 26 of the lecture slides - use the highlighted columns. Also, determine the maximum factored load for the column. 1.5 m 1 m 3m x 2m y = 17 kN/m³ Groundwater level Ysat 19.5 kN/m³ =
For the square foundation shown below, compute the allowable bearing capacity (FS = 3). Use the methodsproposed by Terzaghi, Meyerhof and Vesic.
Solve question 4
Geotechnical question
A square column foundation has to carry a gross allowable load of 1800 kN (FS=3). Determine the size of the foundation (B). The water table locates at the base of the foundation as shown in figure 1. Required modification of the bearing capacity equation has to be conducted due to the location of the GWT. Assume any necessary data if need
(foundation engineering)
QUESTION 5 A 1.8 m x 2.5 m foundation is shown in Figure. If the load eccentricity B 0.45 m and e 0.30 (two-way), determine the allowable load Qall. = 1.6 m ↑ B x L = 1.8 m x 2.5 m c = 0 kN/m² = 34° = 18 kN/m³ Yn Gs = 3
Problem.№₂3 - The plan of a mat foundation is shown in Figure. Calculate the soil pressure at points A, B, C, D, E, and F. (Note: All column sections are planned to be 0.5 m 3 0.5 m.) All loads shown are factored loads according to ACI 381-11 (2011). 550 KN 2000 KN 5.25 m 2000 KN 550 kN F *K 0.25 m G H 10 m ! B i 660 kN 2000 KN 10 m 2000 KN 660 kN E 600 KN 1600 KN 5.25 m 10 m 1600 KN 470 kN C D *K 0.25 m 9 m 9 m 9 m 0.25 m 0.25 m
A 300 mm x 400 mm column is to be supported by 489 m thick square footing @ its center. Service DL= 492 kN, service LL = 917 kN, CC to bar centroid is 90 mm, fc' = 24.32 MPa and fy = 414 MPa. Consider the weight of the footing and soil to be 16.76% of the dead load. SBC = 180 kPa t 300 P 00₺ 300 Note: Present the width (B) in multiples of 100 mm. 400 Determine the required number of 20 mm bars parallel to the critical side.
Q2: Compute the total stresses, which induced from geostatic stress and increase vertical stress from circular foundation under points A and B to 3 and 6 m depth from the base of the foundation. The foundation was constructed at 2.0 m below the natural ground level (NGL). The surface load intensity is 330 kN/m². R1= 4, (calculate R2 from the drawing, do not assume it). Assume any other parameter you need in your answer. Aqs net

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