Q kN/m P KN 1.5 m 3 m 1.5 m x
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Need help solving for Shear force Diagrams and Bending diagrams
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- find out F, KN F23 f13 f16For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm ニ d' = 100mm fc' = 32MPA %3D fy = 400MPA As = 8 - 32mm bars ニ The answer is kN/m Pu = 20 KN %3D bf 3Pu O-50 Pu 七キ Wu 5m As 13 + bw *For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm d' = 100mm fc' = 32MPa fy: 400MPa As = 8-32mm bars The answer is kN/m = 1m A Pu = 20 KN 3Pu Wu 5m 0.50 Pu ff ym 1B3 d bf As + bw-t + 1 tf 1
- Situation 1: A W8x67 has a length of 7.50 m. Fy- 248 MPa. The properties are given below. Properties of W shape A = 12,700 mm^2 d=229 mm bf = 210 mm tf-23.7 mm kdes - 33.8 mm tw - 14.5 mm rx - 94.5 mm ry-53.80 mm 1. Which of the following most nearly gives the axial capacity (Pu) of the column if both are pinned? 1019 KN 1001 KN 1111 KN 979 KNA horizontal beam ABC is loaded as shown in figure below. The distance of the point of contraflexure from end A (in m) is 10KN beol C s no 2tos A 0.75m B o msed 6 1 mA circular V-belt has an inner radius of 600 mm and a cross-sectional area as shown. Determine the volume of material required to make the belt.
- Fill in the blanks: For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm d' = 100mm fc' = 32MPA fy = 400MPA As = 8-32mm bars %3D The answer is kN/m Pu = 20 KN bf 3Pu O-50 Pu 1m As A 13 + bw + CS Scanned with CamScannerCalculate the stress in each segment1/ Calculate maximum deflection of the beams 2/ Check the suitability of the section assuming the code limitation of L/240. 3/ If maximum deflection doesn’t meet the code requirement, propose your solution UKB 457 x 152x 82 Steel: Section properties: I=366,000,000 mm4, E=2*(10)5 N/mm2
- Q3/ A rigid beam ABCD shown in Figure with negligible weight is pinned at one end and attached to two vertical rods. If the beam is subjected to load of P=60 kN. Find the vertical movement at D. Aluminum A- s mm Steel E- 68000 MP L-2 A-300 E- 200000 MPa D 60 KN | Im Im IImFor the given properties of the beam below, determine the safest wu that the beam will carry. bf = 850mm bw = 400mm tf = 100mm %3D d = 400mm d' = 100mm fc' = 34MPA fy = 400MPA As = 8-32mm bars %3D The answer is kN/m Pu bf キ 50 KN (Factore d) load Wu As t. A 5m + bw +PLS PROVIDE COMPLETE SOLUTION THANKS