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It is desired to lay off certain horizontal distances for building layouts. The length of the tape used in the cases below is not 100.00 ft. Determine the field dimensions (or actual tape readings) that should be used with the incorrect tape lengths so that the correct (true) dimensions are obtained. Desired Dimension Correct Tape Length 180.00 ft x 725.00 ft 99.96 ft Field dimensions of the readings (L): The equations for distance correction is: L CDs = L + * STDL (CTL-STD₁) or CDs = L (1 + (CTL-STDL) (DL)) or CDs = L * CTL STDL ST DL CDs=L+(L/STDL)* (CTL-STD₁) (OneNote Equation) or CDs= L*CT₁/STDL (OneNote Equation) WEEK 07 Page 4 (a) Desired dimensions: (180.00 ft. x 725.00 ft.)

It is desired to lay off certain horizontal distances for building layouts. The length of the tape used in the cases below is not 100.00 ft. Determine the field dimensions (or actual tape readings) that should be used with the incorrect tape lengths so that the correct (true) dimensions are obtained. Desired Dimension Correct Tape Length 180.00 ft x 725.00 ft 99.96 ft Field dimensions of the readings (L): The equations for distance correction is: L CDs = L + * STDL (CTL-STD₁) or CDs = L (1 + (CTL-STDL) (DL)) or CDs = L * CTL STDL ST DL CDs=L+(L/STDL)* (CTL-STD₁) (OneNote Equation) or CDs= L*CT₁/STDL (OneNote Equation) WEEK 07 Page 4 (a) Desired dimensions: (180.00 ft. x 725.00 ft.)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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It is desired to lay off certain horizontal distances for building layouts. The length of the tape used in the cases below is not 100.00 ft. Determine the field dimensions (or actual tape readings) that should be used with the incorrect tape lengths so that the correct (true) dimensions are obtained. Desired Dimension Correct Tape Length 180.00 ft x 725.00 ft 99.96 ft Field dimensions of the readings (L): The equations for distance correction is: L CDs = L + * STDL (CTL-STD₁) or CDs = L (1 + (CTL-STDL) (DL)) or CDs = L * CTL STDL ST DL CDs=L+(L/STDL)* (CTL-STD₁) (OneNote Equation) or CDs= L*CT₁/STDL (OneNote Equation) WEEK 07 Page 4 (a) Desired dimensions: (180.00 ft. x 725.00 ft.)
Transcribed Image Text:It is desired to lay off certain horizontal distances for building layouts. The length of the tape used in the cases below is not 100.00 ft. Determine the field dimensions (or actual tape readings) that should be used with the incorrect tape lengths so that the correct (true) dimensions are obtained. Desired Dimension Correct Tape Length 180.00 ft x 725.00 ft 99.96 ft Field dimensions of the readings (L): The equations for distance correction is: L CDs = L + * STDL (CTL-STD₁) or CDs = L (1 + (CTL-STDL) (DL)) or CDs = L * CTL STDL ST DL CDs=L+(L/STDL)* (CTL-STD₁) (OneNote Equation) or CDs= L*CT₁/STDL (OneNote Equation) WEEK 07 Page 4 (a) Desired dimensions: (180.00 ft. x 725.00 ft.)
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