Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 6, Problem 6.9P
A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: Df = 1.5 m, ф′ = 25°, c′ = 70 kN/m2. Using Eq. (6.28) and FS = 3, determine the net allowable load [see Eq. (6.24)] the foundation could carry.
Figure P6.9
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A square foundation is shown in Figure P4.12. Use FS = 6, and determine the size of the foundation. Use Prakash and Saran theory [Eq. (4.55)].
A column foundation (Figure P4.5) is 3 m x 2 m in plan. Given: Df = 1.5 m, Φ' = 25°, c' = 70 kN/m2. Using Eq. (4.26) and FS = 3, determine the net allowable load [see Eq. (4.22)] the foundation could carry.
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Chapter 6 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 6 - For the following cases, determine the allowable...Ch. 6 - A 5.0 ft wide square footing is placed at 3.0 ft...Ch. 6 - Prob. 6.3PCh. 6 - Redo Problem 6.2 using the general bearing...Ch. 6 - The applied load on a shallow square foundation...Ch. 6 - A 2.0 m wide continuous foundation carries a wall...Ch. 6 - Determine the maximum column load that can be...Ch. 6 - A 2.0 m wide strip foundation is placed in sand at...Ch. 6 - A column foundation (Figure P6.9) is 3 m × 2 m in...Ch. 6 - For the design of a shallow foundation, given the...
Ch. 6 - An eccentrically loaded foundation is shown in...Ch. 6 - Prob. 6.12PCh. 6 - For an eccentrically loaded continuous foundation...Ch. 6 - A 2 m 3 m spread footing placed at a depth of 2 m...Ch. 6 - Prob. 6.15PCh. 6 - A tall cylindrical silo carrying flour is to be...Ch. 6 - A 2.0 m 2.0 m square pad footing will be placed...Ch. 6 - An eccentrically loaded continuous foundation is...Ch. 6 - A square foundation is shown in Figure P6.19. Use...Ch. 6 - The shallow foundation shown in Figure 6.25...Ch. 6 - Consider a continuous foundation of width B = 1.4...
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- A square foundation is shown in Figure P6.19. Use FS = 6,and determine the size of the foundation. Use Prakash and Saran's method [Eq. (6.59)].arrow_forwardAn eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 4 ft 2 ft Figure P6.18 Qu 2 ft → -5 ft Y = 105 lb/ft³ Groundwater table Ysat 118 lb/ft³ c' = 0 $' = 35° =arrow_forwardProb. 3): A square shallow foundation is shown below. If the load eccentricity is 0.3 m, determine the maximúm allowable load that the foundation can carry. Use Mayerhof's method, and FS as 4. (Eccentricity in one direction only) e = 0.3 m Qal Y = 16.3 kN/m3 c' = 20 kN/m? p'=28° 1.0 m 1.5 m X 1.5 m Centerlinearrow_forward
- An eccentrically loaded continuous foundation is shown in Figure P4.11. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (4.63)].arrow_forwardA column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, o' = 25°, c' = 50 kN/m². Using Eq. (3.23) and FS = 4, determine the net allowable load [see Eq. (3.15)] the foundation could carry. Use bearing capac- ity, shape, and depth factors given in Şection 3.6.arrow_forwardA continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.arrow_forward
- For an eccentrically loaded continuous foundation on sand, given B = 1.8 m, Df = 0.9 m, e/B = 0.12 (one-way eccentricity), γ = 16 kN/m3, and Φ' = 35°. Using the reduction factor method [Eq. (4.60)], estimate the ultimate load per unit length of the foundation.arrow_forwardA square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, γ = 15.9 kN/m3 ϕ = 34 and c′ = 0. Use Terzaghi’s equation to determine the size of the foundation (B). The applied load on a shallow square foundation makes an angle of 15° with the vertical. Given: B = 1.83 m, Df = 0.91 m, γ = 18.08 kN/m3 ,ϕ=25° , and c′ = 23.96 kN/m2 . Use FS = 4 and determine the gross allowable (vertical component) load. Use Eq. (16.9).arrow_forwardAn eccentrically loaded foundation is shown in Figure P3.9. Use FS of 4 and determine the maximum allowable load that the foundation can carry. Use Meyerhof's effective area method and the bearing capacity, shape, and depth factors given in Section 3.6.arrow_forward
- " (a) Qu 1 Qu 3 B (b) M M → X M Qu M (c) Figure 4.24 Analysis of foundation with two-way eccentricity 7 = 17kN/m³ friction angle = : 35⁰° , and cohesion c = 0 Qu (d) The shallow foundation is shown in Figure 4.24 measures 1.5 m X 2.25 m and is subjected to a centric load and a moment. If ев = = 0.12m e₁ eL = 0.36m and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weightarrow_forwardSolve both questions please!!arrow_forwardsubject : Geotechnical DesignBook : PRINCIPLE OF FOUNDATION ENGINEERINGarrow_forward
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