1. Wastewater samples were prepared and incubated at 20°C for 5 days for BOD analysis. Sample dilutions and the corresponding initial and final dissolved oxygen concentrations are summarized in the following table. Using the correct dilutions, estimate BODS. Estiamte ultimate BOD if the BOD rate constant is 0.36/d. Final DO Bottle Initial Sample Volume DO 9.1 8.5 9.0 6.3 15 9.0 1.2 40 8.9 0.2 1234
1. Wastewater samples were prepared and incubated at 20°C for 5 days for BOD analysis. Sample dilutions and the corresponding initial and final dissolved oxygen concentrations are summarized in the following table. Using the correct dilutions, estimate BODS. Estiamte ultimate BOD if the BOD rate constant is 0.36/d. Final DO Bottle Initial Sample Volume DO 9.1 8.5 9.0 6.3 15 9.0 1.2 40 8.9 0.2 1234
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Normality = Molarity (exchange in electron) =M(Z)
%3D
IEanions - Ecations | < 0.1065 + 0.0155 anions
Henry's Law: x, = K#P,
p= ionic strength =-ECz?
log y = logy, = -÷f( - 0.2(4)]
%3D
1+y/
PV = nRT (R= 0.08206 L-atm/(mol-K))
BOD, = (DO,
DO,)/P
BOD, = [(DO, - DO,) - (B, - B) • fI/P
300-V,
P = V,/300
300
BOD,
= BOD, • (1 – e-kt)
kT, = kr2072) where 0 = 1.057 (T is 20-30) & = 1.136 T<20C
%3D
Least Squares Method:
na + bžy – Ey' = 0; ały + bEy2 - Eyy' = 0
BOD, =-
k -b
MPN
Thomas Equation:
# of positive tubes-100
100mL (ml sample in negative tubes-mL sample in all tubes)+/2
Cr =
; D, = (e-Kt-e-Kt) + Da(e*rt):
K,-Ka
%3D
DRAF
Qw+Qr
(1– Pa(kr-ka):
kala
Dmax =L,e-k,c)
kr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fded4d143-e6bc-43a7-af80-2ef19d02a5d5%2F41c4d432-fe42-4f6a-81ca-1ccfb1906aa2%2Fb51kfxl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Normality = Molarity (exchange in electron) =M(Z)
%3D
IEanions - Ecations | < 0.1065 + 0.0155 anions
Henry's Law: x, = K#P,
p= ionic strength =-ECz?
log y = logy, = -÷f( - 0.2(4)]
%3D
1+y/
PV = nRT (R= 0.08206 L-atm/(mol-K))
BOD, = (DO,
DO,)/P
BOD, = [(DO, - DO,) - (B, - B) • fI/P
300-V,
P = V,/300
300
BOD,
= BOD, • (1 – e-kt)
kT, = kr2072) where 0 = 1.057 (T is 20-30) & = 1.136 T<20C
%3D
Least Squares Method:
na + bžy – Ey' = 0; ały + bEy2 - Eyy' = 0
BOD, =-
k -b
MPN
Thomas Equation:
# of positive tubes-100
100mL (ml sample in negative tubes-mL sample in all tubes)+/2
Cr =
; D, = (e-Kt-e-Kt) + Da(e*rt):
K,-Ka
%3D
DRAF
Qw+Qr
(1– Pa(kr-ka):
kala
Dmax =L,e-k,c)
kr
![Topics Covered: Water Quality
1. Wastewater samples were prepared and incubated at 20°C for 5 days for BOD analysis.
Sample dilutions and the corresponding initial and final dissolved oxygen
concentrations are summarized in the following table. Using the correct dilutions,
estimate BOD5. Estiamte ultimate BOD if the BOD rate constant is 0.36/d.
Bottle
Sample
Volume
Initial
Final DO
DO
1
1
9.1
8.5
9.0
6.3
15
9.0
1.2
40
8.9
0.2
234](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fded4d143-e6bc-43a7-af80-2ef19d02a5d5%2F41c4d432-fe42-4f6a-81ca-1ccfb1906aa2%2Fvdbzb7j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Topics Covered: Water Quality
1. Wastewater samples were prepared and incubated at 20°C for 5 days for BOD analysis.
Sample dilutions and the corresponding initial and final dissolved oxygen
concentrations are summarized in the following table. Using the correct dilutions,
estimate BOD5. Estiamte ultimate BOD if the BOD rate constant is 0.36/d.
Bottle
Sample
Volume
Initial
Final DO
DO
1
1
9.1
8.5
9.0
6.3
15
9.0
1.2
40
8.9
0.2
234
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