AA רואד רחר בורו Determine the size (diameter and depth) of the secondary clarifier (s) at a municipal activated sludge treatment facility: The wastewater flow is 25,000 m³/d, the recycle ratio (recycle sludge flow/wastewater flow) is 0.25. The suspended solids concentration is assumed to be 2500 mg/L in the activated sludge tank. The over flow rate is 50 m3/d- m2 and solids loading is 125 kg/d-m2. Estimate detention time if the depth is 4.5 m. What would be the weir loading?

AA רואד רחר בורו Determine the size (diameter and depth) of the secondary clarifier (s) at a municipal activated sludge treatment facility: The wastewater flow is 25,000 m³/d, the recycle ratio (recycle sludge flow/wastewater flow) is 0.25. The suspended solids concentration is assumed to be 2500 mg/L in the activated sludge tank. The over flow rate is 50 m3/d- m2 and solids loading is 125 kg/d-m2. Estimate detention time if the depth is 4.5 m. What would be the weir loading?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: There is a sedimentation tank that is used to remove suspended solid particles (diameter of 100 um…

A: Given Data : ρp=2650 kg/m3 ρf=999.7 kg/m3 Dp=100×10-6 m μ=1.307×10-3 Ns/m2

Q: Name:.. 11. An activated sludge system has a single aeration basin with a volume of 300,000 gal and…

Q: An activated sludge treatment system to treat a wastewater flow rate of 0.3 m/s of primary effluent.…

Q: 1. The required reactor detention time, 0. 2. The reactor basin volume, V, in m³. 3. The net waste…

Q: After primary treatment, a municipal wastewater contains 150 mg/L BOD5. The wastewater flow of 0.44…

A: Given: Influent BOD, S0=150mg/L Discharge through the aeration tank=0.44cumec HRT=6hr…

Q: 2. The average wastewater flow from a community of 20,000 is 125 gpcd. The 5 day, 20 deg C BOD is…

A: Population = 20000To Find:1) Settling tank surface area2) Settling tank diameter3) BOD removal in…

Q: A detention pond receives wastewater having a constituent concentration of 500 mg/L. A discharge…

A: Solution Given Data constituent Concentration = 500 mg/L Discharge concentration= 100 mg/L Flow…

Q: The design flow for a water treatment plant (WTP) is 7.2 x 103 m³/d. The rapid mixing tank will have…

A: Given Data:The design flow for the WTP is Q=7.2x103 m3/day.The average alum dosage is da=50 mg/L.The…

Q: The chloride concentration in a brine waste flow of 6.3 L/s is 15000 mg/L. The river flow upstream…

A: step 1-

Q: The wastewater contains 7.5 x 105 fecal CFU per liter. The maximum permissible fecal coliform…

A: Given: Initial coliform concentration, Co = 7.5 x 105 CFU/L Maximum permissible coliform…

Q: At the point of mixing of a river and a wastewater point discharge, DO is 5.5 mg/L and DOs is 10.1…

A: It is required to find critical deficit of DO and minimum DO. Critical time of DO deficit and…

Q: Wastewater from a primary treatment tank is to undergo secondary treatment in an activated sludge…

A: Given data-Hydraulic retention time (t) is 6hMean cell residence time is 7 daysBOD content at inlet…

Q: In activated sludge system, SRT is governed by

A: Activated sludge system:

Q: what aerobic reactor volume and operating SRT are required to treat a 20 MGD domestic wastewater…

A: Activated sludge process Assumptions All the reaction occurred in the aeration tank only The…

Q: For a sand filtration device, the flow rate of the influent is 30 m3/day with the sand filter area…

A: Given:- The flow rate of the influent is 30 m3/day The sand filter area of 10 m2 To determine:-…

Q: 1. A natural water with a flow of 4.0 MGD is to be treated with a commercial-grade alum dosage of 80…

Q: There is sedimentation tank that is used to remove suspended solid particles from an incoming…

A: Given Discharge= 150m3/hr surface area= 15m2

Q: 5) The town of Camp Verde has been directed to upgrade its primary Wastewater Treatment Plant (WWTP)…

A: Aeration Tank: The aeration tank is the tank in which wastewater is mixed with the sludge and it is…

Q: a) A wastewater treatment plant consists of primary treatment followed by an activated-sludge…

A: Mesophilic digestion takes place in a mesophilic anaerobic digester which is an anaerobic digestion…

Q: 10. A 15,000 ft" conventional activated sludge system has a recycle ratio of 0.38, an influent flow…

Q: The minimum temperature of the water is 5 °C, the free chlorine residual in the effluent from the…

Q: sand bed filter is 50 ft in diameter and filled to a depth of 20 ft with sand. The sand particle…

Q: A CMAS treatment system must be designed for a municipal wastewater and the following operating…

A: The given data is: BOD5=0.39m3/s VSS in the aeration tank=4300 mg/L 55 g VSS=100 gm soluble BODs…

Q: 12.50 Determine the activated-sludge aeration volume required to treat 2.64 mgd with a BOD of 120…

A: The objective of the question is to determine the aeration volume, MLSS, sludge age, and the…

Q: 2. The average wastewater flow from a community of 20,000 is 125 gpcd. The 5 day, 20 deg C BOD is…

A: Population = 20000To Find:1) Settling tank surface area2) Settling tank diameter3) BOD removal in…

Q: After primary treatment, a municipal wastewater contains 150 mg/L BOD5. The wastewater flow of 0.44…

A: To determine- Aeration volume (m3)

Concept explainers

Integrated Solid Waste Management

Integrated Solid Waste Management (ISWM) is a thorough waste suppression, compost, removal and recycling Program. An effective ISWM system considers how to suppress, manage and recycle solid waste in a manner that is most efficiently to protect human health and the surrounding. ISWM system requires evaluation of public wants and demands and then selecting and merging the most effective waste management activities for the proposed demands. The main ISWM activities for solid waste management are Waste prevention, Recycling and Composting, and Combustion and Removal and waste collection in a properly planned, constructed, managed and mitigated landfill areas. Each of these requires careful designing, financing, accumulation, and delivery of activities.

Question

C.
What is the concentration UI SUINUS
5. Determine the size (diameter and depth) of the secondary clarifier (s) at a municipal
activated sludge treatment facility: The wastewater flow is 25,000 m³/d, the recycle
ratio (recycle sludge flow/wastewater flow) is 0.25. The suspended solids concentration
is assumed to be 2500 mg/L in the activated sludge tank. The over flow rate is 50 m3/d-
m2 and solids loading is 125 kg/d-m2. Estimate detention time if the depth is 4.5 m.
What would be the weir loading?
Department of Civil & Environmental Engineering
P.O. Box 519 Mail Stop 2510, Prairie View, Texas 77446
w.pvamu.edu
Phone (936) 261-1660/1665(dept)
Fax (936) 261 1662
Ensuring
o Using Zoom o

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

- An aerobic digester with a total capacity of 50,000 ft³ stabilize waste-activated sludge from an extended-aeration treatment plant without primary clarification. The average daily sludge flow pumped to the digestion tanks is 32,000 gpd with 1.5% solids, of which 65% are volatile. Calculate a) sludge detention time in the digesters b) the amount of sludge produced daily and c) the anaerobic digester dimensions. The population being served is 75,000. SS and BOD = 350 mg/l. %3D
The characteristics of the synthetic textile wastewater are 1500 mg/L BOD, 2000 mg/L SS, 30 mg/L nitrogen, and no phosphorus. The characteristics of the domestic wastewater are 200 mg/L BOD, 240 mg/L SS, 35 mg/L nitrogen, and 7 mg/L phosphorus. Find the nitrogen concentrations in the mixture. The ratio of flow rate is domestic/textile = 4/1
2. The average wastewater flow from a community of 20,000 is 125 gpcd. The 5 day, 20 deg C BOD is 250 mg/L. The suspended solids content is 300 mg/L. A final plant effluent of 50 mg/L of BOD is to be achieved through the use of two sets of identical settling tanks and trickling filters operating in parallel. The settling tanks are to be designed to a standard of 1000 gpd/^2. The trickling filters are to be 6^ deep and operated at an organic loading of 55 lbm/1000^3 d. There is no recirculalon. (1) What settling tank surface area is required? In ft^2 (2) What settling tank diameter is required? In ft (3) Estimate the BOD removal in the settling tanks? In percent % (4) What is the trickling filter diameter? In ft domeved Ward
Two circular clarifiers operated in parallel service a single stage bio-tower system (plastic media) that receives municipal wastewater at an average flow (Qaverage) of 2000 m³/d, with BOD5 = 200 mg/L. The internal flow recirculation ratio is 2.4. The maximum overflow rate for the clarifiers is 1.8 m³/m²-hr. The design procedures require that the sizing of the clarifiers be based on "PEAK" flow which is twice the average flow (Qpeak = 2 × Qaverage), and media depth in the biotower is 3.0 m. Determine: (a) The overall BOD5 removal. (b) the surface area and the diameter of each clarifier. (k = 0.06 min¹; n = 0.5),
An activated sludge wastewater treatment system was designed and operated in a steadystate under the following conditions:• Reactor volume of 10,000 m3in total;• Sludge concentration (MLSS) of 3200 mg/L in the reactor;• Return sludge concentration at 8000 mg/L (the underflow of the secondary clarifier)• Each day, 400 m3 of underflow sludge (return sludge) was wasted as excesssludge;What is the average Sludge Residence Time (SRT)?
A complete mix activated sludge process treats 5 MGD of wastewater containing a total BOD5 concentration of 225 mg/L BOD5 to 20 mg/L BOD5, which is 75% soluble in both the influent and the effluent. The volume of the aeration basin is 111,400 ft3 and the MLSS concentration is 2500 mg/L. Determine the following: a) Detention time in the aeration basin (hr) b) F/M ratio c) Specific substrate utilization rate d) Substrate removal efficiency
As an operator of a wastewater treatment facility, you have learned that your plant runs well at an SRT (based on MLVSS (X) in the aeration basin) of 12 days. If today’s MLVSS (X) concentration is 2,700 mg/L and the RAS (Xr) concentration is 5,500 mg/L, how many L of sludge should you waste from the secondary clarifier today? Other design conditions: Average influent flow = 12,000 m3/d Influent soluble BOD = 150 mg/L Required effluent TSS = 30 mg/L Aeration tank Volume = 1,000 m3