In a BOD test, the amount of organic matter remaining in the wastewater was measured at certain time intervals, instead of measuring the dissolved oxygen content. The amount of organic matter remaining after 4 and 9 d was measured as 52.86 mg/L and 8.11 mg/L, respectively. Calculate the ultimate BOD and BOD rate constant k for the wastewater.

Q: For a wastewater sample, the three-day biochemical oxygen demand at incubation temperature of 20°C…

A: Given data- BOD at 3 days at 20o=200 mg/Lk=0.22 day-1To Find-BOD at 5 days at 20o

Q: A wastewater sample is experimented for 5-day BOD at 20°C and it is found to be 120 mg/L. If the…

A:

Q: Question The domestic sewage of a town was tested for total solids and the following results were…

A: Given data- The details of the domestic sewage of a town given- Weight of the sample of sewage =…

Q: A wastewater sample of 2 ml is made up to 300 ml in a BOD bottle with distilled water. The initial…

A: Given- water sample volume=2 mL300 mL BOD bottleInitial DO=8 mg/LFinal DO=2 mg/LBOD=?

Q: A 8.5 ml of sample of wastewater is diluted to 300 ml with distilled water in standard biochemical…

A:

Q: The concentration of dissolved oxygen in a sample of waste water decreases from 9 x 10^3 g/L to 6.2…

A: Given data, Initial Concentration of DO = 9×103 g/l Final Concentration of DO = 6.2×103 g/l  Number…

Q: The following data pertains to a sewage sample at a point source. Initial dissolved oxygen (DO) = 12…

A: Given data- Initial DO=12 mg/LFinal DO=4 mg/Ldilution=2%To Find-BOD of the sample

Q: A wastewater sample is experimented for 5-day BOD at 20°C and it is found to be 120 mg/L. If the…

A: given 5 day BOD =120mg/ltreaction rate k=0.414/dayt=5daysfind the ultimate BOD…

Q: Problem #7: A domestic sewage analysis was carried out for solid analysis. The test was performed…

A: Hi there!! since you have asked multiple questions, we will solve the first question for you. If you…

Q: If the BOD3 of a wastewater sample is 75 mg/l and reaction rate constantk (base e) is 0.345 per day,…

A:

Q: 5) The permit for a wastewater treatment facility states that the plant can discharge no more than 5…

A: given - maximum allowable phosphorus per day = 5 pounds  design flow = 12 million gallons per day…

Biological Processes

Biological solid waste includes bacterial and contaminated waste produced by living individuals. Its treatment is essential to prevent the spread of any air-borne or water-borne diseases or diseases transmitted from one organism to another in a food chain. There are many benefits of the biological solid waste treatment and some of them are: the minimized quantity of waste substance, waste control, eradicating any disease-causing pathogens, generation of biogas, composting, anaerobic digestion, bio drying, mechanical biological treatment, microbial fuel cell, phytoremediation, and biofiltration. The final products of the biological solid waste treatment may be recycled to obtain organic fertilizers or disposed of in SWDS (Solid Waste Disposal Site) after proper treatment.