1. For each of the following h(t) and x(t), characterize the output of the continuous-time LTI system with impulse response h(t) and input x(t): a. h(t) = u(t + 1) — u(t − 1) and x(t) = (1 − e−t)u(t). b. h(t) = 8(t − 1) + 38(3 − t) and x(t) = cos(t). c. h(t) = e2tu(t) and x(t) = u(t). d. h(t) = e¯atu(t) and x(t) = e¯btu(t) for a, b > 0. e. h(t) = e¹u(−t + 1) and x(t) = t[u(t + 1) − u(t − 2)]
1. For each of the following h(t) and x(t), characterize the output of the continuous-time LTI system with impulse response h(t) and input x(t): a. h(t) = u(t + 1) — u(t − 1) and x(t) = (1 − e−t)u(t). b. h(t) = 8(t − 1) + 38(3 − t) and x(t) = cos(t). c. h(t) = e2tu(t) and x(t) = u(t). d. h(t) = e¯atu(t) and x(t) = e¯btu(t) for a, b > 0. e. h(t) = e¹u(−t + 1) and x(t) = t[u(t + 1) − u(t − 2)]
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![1. For each of the following h(t) and x(t), characterize the output of the continuous-time LTI system with impulse
response h(t) and input x(t):
a. h(t) = u(t + 1) — u(t − 1) and x(t) = (1 − e−t)u(t).
b. h(t) = 8(t − 1) + 38(3 − t) and x(t) = cos(t).
c. h(t) = e2tu(t) and x(t) = u(t).
d. h(t) = e¯atu(t) and x(t) = e¯btu(t) for a, b > 0.
e. h(t) = e¹u(−t + 1) and x(t) = t[u(t + 1) − u(t − 2)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feaf923b1-621b-4242-8f85-61b87d833819%2F36e05a4e-9394-43eb-9ba1-07d8c304a9f1%2Fgqilc2a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. For each of the following h(t) and x(t), characterize the output of the continuous-time LTI system with impulse
response h(t) and input x(t):
a. h(t) = u(t + 1) — u(t − 1) and x(t) = (1 − e−t)u(t).
b. h(t) = 8(t − 1) + 38(3 − t) and x(t) = cos(t).
c. h(t) = e2tu(t) and x(t) = u(t).
d. h(t) = e¯atu(t) and x(t) = e¯btu(t) for a, b > 0.
e. h(t) = e¹u(−t + 1) and x(t) = t[u(t + 1) − u(t − 2)]
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