A PN junction diode has the following doping profile around the metallurgical junction. For this junction, sketch the expected: (a) Charge density (b) Electric field (c) Electrostatic potential inside the diode based on the depletion approximation. NA - ND -No Problem 3 For the PN junction diode in problem 2, derive the analytical expressions for the: (a) Electric field distribution as a function of x (b) Electrostatic potential distribution as a function of x (c) Built-in potential Assuming the doping is ND for x < 0 and NA - ND = ax for x≥0. The semiconductor permittivity is €5. You can leave your answers in terms of constants provided in the problem, e.g. ND, NA, α, x, xn and Es

Electric Motor Control
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Author:Herman
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Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
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A PN junction diode has the following doping profile around the metallurgical junction. For this junction,
sketch the expected:
(a) Charge density
(b) Electric field
(c) Electrostatic potential
inside the diode based on the depletion approximation.
NA - ND
-No
Problem 3
For the PN junction diode in problem 2, derive the analytical expressions for the:
(a) Electric field distribution as a function of x
(b) Electrostatic potential distribution as a function of x
(c) Built-in potential
Assuming the doping is ND for x < 0 and NA - ND = ax for x≥0. The semiconductor permittivity is €5.
You can leave your answers in terms of constants provided in the problem, e.g. ND, NA, α, x, xn and Es
Transcribed Image Text:A PN junction diode has the following doping profile around the metallurgical junction. For this junction, sketch the expected: (a) Charge density (b) Electric field (c) Electrostatic potential inside the diode based on the depletion approximation. NA - ND -No Problem 3 For the PN junction diode in problem 2, derive the analytical expressions for the: (a) Electric field distribution as a function of x (b) Electrostatic potential distribution as a function of x (c) Built-in potential Assuming the doping is ND for x < 0 and NA - ND = ax for x≥0. The semiconductor permittivity is €5. You can leave your answers in terms of constants provided in the problem, e.g. ND, NA, α, x, xn and Es
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